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Vlada [557]
2 years ago
8

A bridge that was 5m long has been washed out by a heavy rain. The road on the

Physics
1 answer:
amid [387]2 years ago
8 0
Hello so first of all you put 2m in the and you timesand then i’ve got your answer
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Radiation from the Sun The intensity of the radiation from the Sun measured on Earth is 1360 W/m2 and frequency is f = 60 MHz. T
Zina [86]

a) Total power output: 3.845\cdot 10^{26} W

b) The relative percentage change of power output is 1.67%

c) The intensity of the radiation on Mars is 540 W/m^2

Explanation:

a)

The intensity of electromagnetic radiation is given by

I=\frac{P}{A}

where

P is the power output

A is the surface area considered

In this problem, we have

I=1360 W/m^2 is the intensity of the solar radiation at the Earth

The area to be considered is area of a sphere of radius

r=1.5\cdot 10^{11} m (distance Earth-Sun)

Therefore

A=4\pi r^2 = 4 \pi (1.5\cdot 10^{11})^2=2.8\cdot 10^{23}m^2

And now, using the first equation, we can find the total power output of the Sun:

P=IA=(1360)(2.8\cdot 10^{23})=3.845\cdot 10^{26} W

b)

The energy of the solar radiation is directly proportional to its frequency, given the relationship

E=hf

where E is the energy, h is the Planck's constant, f is the frequency.

Also, the power output of the Sun is directly proportional to the energy,

P=\frac{E}{t}

where t is the time.

This means that the power output is proportional to the frequency:

P\propto f

Here the frequency increases by 1 MHz: the original frequency was

f_0 = 60 MHz

so the relative percentage change in frequency is

\frac{\Delta f}{f_0}\cdot 100 = \frac{1}{60}\cdot 100 =1.67\%

And therefore, the power also increases by 1.67 %.

c)

In this second  case, we have to calculate the new power output of the Sun:

P' = P + \frac{1.67}{100}P =1.167P=1.0167(3.845\cdot 10^{26})=3.910\cdot 10^{26} W

Now we want to calculate the intensity of the radiation measured on Mars. Mars is 60% farther from the Sun than the Earth, so its distance from the Sun is

r'=(1+0.60)r=1.60r=1.60(1.5\cdot 10^{11})=2.4\cdot 10^{11}m

Now we can find the radiation intensity with the equation

I=\frac{P}{A}

Where the area is

A=4\pi r'^2 = 4\pi(2.4\cdot 10^{11})^2=7.24\cdot 10^{23} m^2

And substituting,

I=\frac{3.910\cdot 10^{26}}{7.24\cdot 10^{23}}=540 W/m^2

Learn more about electromagnetic radiation:

brainly.com/question/9184100

brainly.com/question/12450147

#LearnwithBrainly

4 0
3 years ago
Write a hypothesis about the use of an object’s physical characteristics to determine its density. Use the format "if . . . then
mash [69]
For this case you must first know the definition of density.
 D = m / v
 where,
 m: mass
 v: volume.
 You can then write the following hypothesis:
 IF you know two physical characteristics of an object then you can determine the density. First weigh the object, THEN measure its volume BECAUSE the density is the quotient between the mass and the volume of an object.
5 0
3 years ago
Read 2 more answers
HELP ASAP!!!! Which of the following is an example of a hypothesis? A) What will happen if a sugar cube in boiling water? B) I t
Maurinko [17]

Answer:

C) If an ice cube is placed into a boiling water, then it will melt in less than 2 minutes.

Explanation:

7 0
3 years ago
How many significant figures are in 246.32
muminat

Answer:5

Explanation:

Decimal :2

Significant notation :2.4632× 10^2

8 0
3 years ago
How do the heart and lungs work together?
Readme [11.4K]
This isn't physics, it's biology but basically, when you breath in oxygen, the oxygen goes to the lungs which transfer it to the blood cells. The heart then pumps the blood cells round to the organs, muscles etc and the blood cells drop off the oxygen where necessary, they then pick up carbon dioxide and the heart pumps them to the lungs where the blood cells give the lungs the carbon dioxide and the lungs make you breath the carbon dioxide out (his is a very simplified explanation, I'm not a biologist)
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3 years ago
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