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ziro4ka [17]
2 years ago
9

Please i need asp this is me ether failing or passing math!!!

Mathematics
1 answer:
Citrus2011 [14]2 years ago
8 0

Answer:

 

Step-by-step explanation:

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Find the surface area of the figure.<br> 12 in.<br> SA = [ ? ]in.?<br> 5 in.<br> 16 in.
tekilochka [14]

Answer:

SA = 664 in.²

Step-by-step explanation:

Surface area of the rectangular prism = 2(LW + LH + WH)

Where,

Length (L) = 16 in.

Width (W) = 5 in.

Height (H) = 12 in.

Substitute the values

Surface area of the rectangular prism = 2(16*5 + 16*12 + 5*12)

= 2(80 + 192 + 60)

= 2(332)

= 664 in.²

5 0
2 years ago
 Find sin2x, cos2x, and tan2x if sinx=-15/17 and x terminates in quadrant III
vodka [1.7K]

Given:

\sin x=-\dfrac{15}{17}

x lies in the III quadrant.

To find:

The values of \sin 2x, \cos 2x, \tan 2x.

Solution:

It is given that x lies in the III quadrant. It means only tan and cot are positive and others  are negative.

We know that,

\sin^2 x+\cos^2 x=1

(-\dfrac{15}{17})^2+\cos^2 x=1

\cos^2 x=1-\dfrac{225}{289}

\cos x=\pm\sqrt{\dfrac{289-225}{289}}

x lies in the III quadrant. So,

\cos x=-\sqrt{\dfrac{64}{289}}

\cos x=-\dfrac{8}{17}

Now,

\sin 2x=2\sin x\cos x

\sin 2x=2\times (-\dfrac{15}{17})\times (-\dfrac{8}{17})

\sin 2x=-\dfrac{240}{289}

And,

\cos 2x=1-2\sin^2x

\cos 2x=1-2(-\dfrac{15}{17})^2

\cos 2x=1-2(\dfrac{225}{289})

\cos 2x=\dfrac{289-450}{289}

\cos 2x=-\dfrac{161}{289}

We know that,

\tan 2x=\dfrac{\sin 2x}{\cos 2x}

\tan 2x=\dfrac{-\dfrac{240}{289}}{-\dfrac{161}{289}}

\tan 2x=\dfrac{240}{161}

Therefore, the required values are \sin 2x=-\dfrac{240}{289},\cos 2x=-\dfrac{161}{289},\tan 2x=\dfrac{240}{161}.

7 0
2 years ago
Can someone help with this question
Zielflug [23.3K]

Answer:

<1= 60

<2=120

<3=60

<4=60

<5=120

<6=120

<7=60

Step-by-step explanation:

6 0
2 years ago
A rePrism measures 6.7 cm by 3.2 cm by 9 cm what is the volume of the rectangle prism
Blizzard [7]

Answer:

The volume is 192.96

Step-by-step explanation:

You multiply length x width x height to find the volume.

6 0
3 years ago
Enter the equation of the circle described below.<br><br> Center (-1, 4), radius = √3
lorasvet [3.4K]
EQUATION OF A CIRCLE: (x-h)² + (y-k)² =r²


=  (x+1)² + (y-4)² =3
3 0
3 years ago
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