The x=7y-4 one and put it to where the x in the other equation is.
Based on the information of the table, you have:
1. The ratio is 105/150. By simplifying you get for the ratio 7/10.
2. The students that prefer action movies are 75+90 = 165 and the total numbe of students is 180+240 = 420. Then, the fraction of students who prefer action movies is:
165/420 = 11/28
3. The fraction of seventh graders students that prefer action movies is:
75/180 = 5/12
4. The percent of student that prefer comedy is:
105 + 150 = 255 total student that prefer comedy
420 total number of students
the fraction is:
(x/100)420 = 255
solve for x:
x = 255(100/420)
x = 60.71
the percent of students is 60.71%
5. The percent of eighth graders student who prefer action moveis is:
(x/100)240 = 90
x = 90(100/240)
x = 37.5
the percent of students is 37.5%
6. To determine which from the given grades has the greatest percent of student that prefer action movies, calculate the percent of student in seventh-grade:
(x/100)180 = 75
x = 75(100/180)
x = 41.66
the percent of student is 41.66%
then, seventh grade has the greatest percent of student that prefer action movies.
Answer:
Tan(O) = 4/3
Step-by-step explanation:
According to SOH CAH TOA
cos theta = adj/hyp
cosO = 3/4
adj = 3
hyp = 5
Get the opposite
Using pythagoras theorem
opp^2 = hyp^2-adj^2
opp^2 = 5^2 - 3^2
opp^2 = 25-9
opp^2 = 16
opp = 4
Tan (O) = opp/adj
Tan(O) = 4/3
Hence Tan(O) = 4/3
