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2 years ago

The scale on a map is 2cm = 25 miles. Dave measured the distance to the next town at 5cm. How many miles away is the next town?

Mathematics

2 answers:

lbvjy [14]2 years ago

7 0

Answer: 62.5 miles away.

Step-by-step explanation: divide 25 by 2, than multiply that by 5, you will get 62.5.

Novay_Z [31]2 years ago

3 0

62.5
2=25, 2x2=50
1=12.5. 62.2

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Suppose that during it's flight, the elevation `e` (in feet) of a certain airplane and its time `t,` in minutes since takeoff, a

kifflom [539]

Answer:

Suppose that during its flight, the elevation e (in feet) of a certain airplane and its time ... since takeoff, are related by a linear equation. Consider the graph of this equation, with time represented on the horizontal axis and elevation on the vertical axis. ... Unit 3; Linear Relationships Lesson 9: Slopes Don't Have to be Positive.

Step-by-step explanation:

8 0

2 years ago

It's 16inches tall and the exact model is 40 feet long

OleMash [197]

Ahh... this is pretty easy!!
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Locomotive is 40 feet.
.
Model is 16.
.
So?
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Divide 40 by 16!!
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What's that?
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2.5.
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So your answer choice is 2.5
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Hope I helped!!

4 0

3 years ago

A juggler tosses a ball into the air . The balls height, h and time t seconds can be represented by the equation h(t)= -16t^2+40

malfutka [58]

PART A

The given equation is

$h(t) = - 16 {t}^{2} + 40t + 4$

In order to find the maximum height, we write the function in the vertex form.

We factor -16 out of the first two terms to get,

$h(t) = - 16 ({t}^{2} - \frac{5}{2} t) + 4$

We add and subtract

$- 16(- \frac{5}{4} )^{2}$

to get,

$h(t) = - 16 ({t}^{2} - \frac{5}{2} t) + - 16( - \frac{5}{4})^{2} - -16( - \frac{5}{4})^{2} + 4$

We again factor -16 out of the first two terms to get,

$h(t) = - 16 ({t}^{2} - \frac{5}{2} t + ( - \frac{5}{4})^{2} ) - -16( - \frac{5}{4})^{2} + 4$

This implies that,

$h(t) = - 16 ({t}^{2} - \frac{5}{2} t + ( - \frac{5}{4}) ^{2} ) + 16( \frac{25}{16}) + 4$

The quadratic trinomial above is a perfect square.

$h(t) = - 16 ( t- \frac{5}{4}) ^{2} +25+ 4$

This finally simplifies to,

$h(t) = - 16 ( t- \frac{5}{4}) ^{2} +29$

The vertex of this function is

$V( \frac{5}{4} ,29)$

The y-value of the vertex is the maximum value.

Therefore the maximum value is,

$29$

PART B

When the ball hits the ground,

$h(t) = 0$

This implies that,

$- 16 ( t- \frac{5}{4}) ^{2} +29 = 0$

We add -29 to both sides to get,

$- 16 ( t- \frac{5}{4}) ^{2} = - 29$

This implies that,

$( t- \frac{5}{4}) ^{2} = \frac{29}{16}$

$t- \frac{5}{4} = \pm \sqrt{ \frac{29}{16} }$

$t = \frac{5}{4} \pm \frac{ \sqrt{29} }{4}$

$t = \frac{ 5 + \sqrt{29} }{4} = 2.60$

or

$t = \frac{ 5 - \sqrt{29} }{4} = - 0.10$

Since time cannot be negative, we discard the negative value and pick,

$t = 2.60s$

8 0

3 years ago

A number, x, rounded to 1 decimal place is 3.7<br> Write down the error interval for x.

soldier1979 [14.2K]

Answer: (3.65, 3.74)

Step-by-step explanation:

Now, when we round a number to a given decimal place, we need to look at the decimal to the left of the decimal place where we are rounding.

if it is 5 or more, we round up

if it is smaller than 5, we round down.

Then for example, if we want to round:

4.534

to the first decimal place, we need to look at the second decimal place.

we can see that it is a 2.

Then we round down, and get:

4.5

Now we know that, when rounding to the first decimal place, we have:

x = 3.7

Then the maximum value that x could have is:

x = 3.74 (because here we round down to 3.7)

and the minimum value that x could have is:

x = 3.65 (because here we round up to 3.7)

Then the error interval for x is:

(3.65, 3.74)

6 0

2 years ago

Probability Question

pav-90 [236]

To find the probability that A occurs given B occurs, multiply the Probability of A by the probability of B.

3/4 x 5/8 = 15/32

6 0

3 years ago