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katovenus [111]
3 years ago
9

Solve the equation: .2x(.7x-5)+0.2=1.4(x-1.6)

Mathematics
2 answers:
Ilia_Sergeevich [38]3 years ago
6 0

9514 1404 393

Answer:

  x = 8/7

Step-by-step explanation:

  .2(.7x-5)+0.2=1.4(x-1.6) . . . . given

Eliminating parentheses, we have ...

  0.14x -1 +0.2 = 1.4x -2.24

  1.44 = 1.26x . . . . . . . add 2.24-0.14x to both sides

  x = 1.44/1.26 . . . . . . divide by the coefficient of x

  x = 8/7 . . . . . . . . . . .simplify the fraction

__

As a repeating decimal, the value of x is ...

  x=1.\overline{142857}

However, the notation 1.(142857) is usually reserved for the case where the contents of parentheses are being multiplied by the factor in front. You would need to consult your instructions to see how the decimal version of the answer should be entered. (Quite often, rounding is suggested.)

_____

<em>Additional comment</em>

The equation in the text of your question is different from the one in the picture. We have answered for the one in the picture. The text asks for the solution of a quadratic. Those two solutions are approximately 1.085 and 16.057.

Mama L [17]3 years ago
4 0

Answer:

the answer is x=8/7

Step-by-step explanation:

:)))

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50 points! I understand A. and B. but I would really appreciate help with C.
FromTheMoon [43]

Answer:

51.72\text{ cells per hour}

Step-by-step explanation:

So, the function, P(t), represents the number of cells after t hours.

This means that the derivative, P'(t), represents the instantaneous rate of change (in cells per hour) at a certain point t.

C)

So, we are given that the quadratic curve of the trend is the function:

P(t)=6.10t^2-9.28t+16.43

To find the <em>instanteous</em> rate of growth at t=5 hours, we must first differentiate the function. So, differentiate with respect to t:

\frac{d}{dt}[P(t)]=\frac{d}{dt}[6.10t^2-9.28t+16.43]

Expand:

P'(t)=\frac{d}{dt}[6.10t^2]+\frac{d}{dt}[-9.28t]+\frac{d}{dt}[16.43]

Move the constant to the front using the constant multiple rule. The derivative of a constant is 0. So:

P'(t)=6.10\frac{d}{dt}[t^2]-9.28\frac{d}{dt}[t]

Differentiate. Use the power rule:

P'(t)=6.10(2t)-9.28(1)

Simplify:

P'(t)=12.20t-9.28

So, to find the instantaneous rate of growth at t=5, substitute 5 into our differentiated function:

P'(5)=12.20(5)-9.28

Multiply:

P'(5)=61-9.28

Subtract:

P'(5)=51.72

This tells us that at <em>exactly</em> t=5, the rate of growth is 51.72 cells per hour.

And we're done!

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