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Hunter-Best [27]
3 years ago
9

Find the value of z ANSWER IS NOT 12. NO LINKS OR SPAMS! THANK YOU!!!!!!​

Mathematics
1 answer:
alexgriva [62]3 years ago
4 0

Answer:

12√3

Step-by-step explanation:

sin 30 =1/2

sin30=a/24. sin=opposit side/Hypotenuse

a is the opposite side of 30

1/2=a/24

a=12

now take pythagoras theroem

24^2=z^2+12^2

576=z^2+144

z^2=576-144

z^2=432

z=√432

z=√144*3

z=12√3

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AleksAgata [21]

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Answer:

  64.6

Step-by-step explanation:

One standard deviation is 4.3. Then +2 standard deviations is ...

  (+2)(4.3) = +8.6

This amount added to the mean gives ...

  56 +8.6 = 64.6 . . . . +2σ from the mean

5 0
3 years ago
Use the distributive property to solve 4 × 7.1​
sladkih [1.3K]

Answer:

28.4

Step-by-step explanation:

To use the distributive property, split the 7.1 to 7 and .1

4*7 would be 28 and 4*.1 would be .4

Adding them together would make the answer 28.4

3 0
4 years ago
Please answer these two questions !!!
Roman55 [17]

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3 0
3 years ago
A pipe that is 120 cm long resonates to produce sound of wavelengths 480 cm, 160 cm, and 96 cm but does not resonate at any wave
erma4kov [3.2K]

Answer:

A Pipe that is 120 cm long resonates to produce sound of wavelengths 480 cm, 160 cm and 96 cm but does not resonate at any wavelengths longer than these. This pipe is:

A. closed at both ends

B. open at one end and closed at one end

C. open at both ends.

D. we cannot tell because we do not know the frequency of the sound.

The right choice is:

B. open at one end and closed at one end .

Step-by-step explanation:

Given:

Length of the pipe, L = 120 cm

Its wavelength \lambda_1 = 480 cm

                         \lambda_2 = 160 cm and \lambda_3 = 96 cm

We have to find whether the pipe is open,closed or open-closed or none.

Note:

  • The fundamental wavelength of a pipe which is open at both ends is 2L.
  • The fundamental wavelength of a pipe which is closed at one end and open at another end is 4L.

So,

The fundamental wavelength:

⇒ 4L=4(120)=480\ cm

It seems that the pipe is open at one end and closed at one end.

Now lets check with the subsequent wavelengths.

For one side open and one side closed pipe:

An odd-integer number of quarter wavelength have to fit into the tube of length L.

⇒  \lambda_2=\frac{4L}{3}                                   ⇒  \lambda_3=\frac{4L}{5}

⇒ \lambda_2=\frac{4(120)}{3}                              ⇒  \lambda_3=\frac{4(120)}{5}

⇒ \lambda_2=\frac{480}{3}                                  ⇒  \lambda_3=\frac{480}{5}

⇒ \lambda_2=160\ cm                           ⇒   \lambda_3=96\ cm  

So the pipe is open at one end and closed at one end .

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3 years ago
(50 points)
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The answer is f(x) will eventually exceed g(x) because f(x) is an exponential function.
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