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3 years ago

Find the value of z ANSWER IS NOT 12. NO LINKS OR SPAMS! THANK YOU!!!!!!

Mathematics

1 answer:

alexgriva [62]3 years ago

4 0

Answer:

12√3

Step-by-step explanation:

sin 30 =1/2

sin30=a/24. sin=opposit side/Hypotenuse

a is the opposite side of 30

1/2=a/24

a=12

now take pythagoras theroem

24^2=z^2+12^2

576=z^2+144

z^2=576-144

z^2=432

z=√432

z=√144*3

z=12√3

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Integrate 1 - x / x(x2 + 1) d x by partial fractions.

solniwko [45]

Answer:

$log x-\frac{log(x^{2}+1) }{2}-tan^{-1} x$

Step-by-step explanation:

step 1:- by using partial fractions

$[tex]\frac{1-x}{x(x^{2}+1) } =\frac{A(x^{2}+1)+(Bx+C)(x }{x(x^{2}+1) }$ ......(1)

step 2:-

solving on both sides

$1-x=A(x^{2} +1)+(Bx+C)x......(2)$

substitute x =0 value in equation (2)

1=A(1)+0

A=1

comparing x^2 co-efficient on both sides (in equation 2)

0 = A+B

0 = 1+B

B=-1

comparing x co-efficient on both sides (in equation 2)

-1 = C

step 3:-

substitute A,B,C values in equation (1)

now

$\\\int\limits^ {} \, \frac{1-x}{x(x^{2}+1) } d x =\int\limits^ {} \frac{1}{x} d x +\int\limits^ {} \frac{-x}{x^{2}+1 } d x -\int\limits \frac{1}{x^{2}+1 } d x$

by using integration formulas

i) by using $\int\limits \frac{1}{x} d x =log x+c........(a)\\\int\limits \frac{f^{1}(x) }{f(x)} d x= log(f(x)+c\\$ .....(b)

$\int\limits tan^{-1}x dx =\frac{1}{1+x^{2} } +C$ .....(c)

step 4:-

by using above integration formulas (a,b,and c)

we get answer is

$log x-\frac{log(x^{2}+1) }{2}-tan^{-1} x$

6 0

3 years ago

In a batch of 890 calculators, 12 were found to be defective. What is the probability that a calculator chosen at random will be

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Answer:

1.3%

When entered into a calculator, 12/890 (the chance of a given calculator being defective) = 0.01348...

As a percent this is 100*0.01348% = 1.348%, and to the nearest tenth, 1.3%

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3 years ago

Read 2 more answers

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Dafna11 [192]

Answer:

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Step-by-step explanation:

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kherson [118]

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Find the value of z ANSWER IS NOT 12. NO LINKS OR SPAMS! THANK YOU!!!!!!​

Find the value of z ANSWER IS NOT 12. NO LINKS OR SPAMS! THANK YOU!!!!!!