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AnnyKZ [126]
3 years ago
10

The volume of a gas is increased from 445mL to 515ml. If the initial pressure was 120kPa, what is the final pressure of the gas?

Chemistry
1 answer:
Hoochie [10]3 years ago
6 0

Answer: 103.7 kPa

Explanation:

Given that:

initial volume of gas V1 = 445ml

initial pressure of gas P1 = 120 kPa.

new Volume V2 = 515ml

new pressure P2 = ?

Since, only pressure and volume are involved, apply the formula for Boyle's law

P1V1 = P2V2

120 kPa x 445ml = P2 x 515 kPa

53400 = P2 x 515 kPa

P2 = 53400/515

P2 = 103.7 kPa

Thus, the final pressure of the gas is 103.7 kPa

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Problem Page Liquid hexane will react with gaseous oxygen to produce gaseous carbon dioxide and gaseous water . Suppose 70. g of
shusha [124]

Answer:

The maximum mass of carbon dioxide that could be produced by the chemical reaction is 70.6gCO_{2}

Explanation:

1. Write down the balanced chemical reaction:

2C_{6}H_{14}_{(l)}+19O_{2}_{(g)}=12CO_{2}_{(g)}+14H_{2}O_{(g)}

2. Find the limiting reagent:

- First calculate the number of moles of hexane and oxygen with the mass given by the problem.

For the hexane:

70.0gC_{6}H_{14}*\frac{1molC_{6}H_{14}}{86.2gC_{6}H_{14}}=0.81molesC_{6}H_{14}

For the oxygen:

81.3gO_{2}*\frac{1molO_{2}}{32.0gO_{2}}=2.54molesO_{2}

- Then divide the number of moles between the stoichiometric coefficient:

For the hexane:

\frac{0.81}{2}=0.41

For the oxygen:

\frac{2.54}{19}=0.13

- As the fraction for the oxygen is the smallest, the oxygen is the limiting reagent.

3. Calculate the maximum mass of carbon dioxide that could be produced by the chemical reaction:

The calculations must be done with the limiting reagent, that is the oxygen.

81.3gO_{2}*\frac{1molO_{2}}{32gO_{2}}*\frac{12molesCO_{2}}{19molesO_{2}}*\frac{44.0gCO_{2}}{1molCO_{2}}=70.6gCO_{2}

7 0
3 years ago
1) *
Marizza181 [45]

C

i think i am  sorry if am wrong  

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