=Y2-10Y
We move all terms to the left:
-(Y2-10Y)=0
We add all the numbers together, and all the variables
-(+Y^2-10Y)=0
We get rid of parentheses
-Y^2+10Y=0
We add all the numbers together, and all the variables
-1Y^2+10Y=0
a = -1; b = 10; c = 0;
Δ = b2-4ac
Δ = 102-4·(-1)·0
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
Y1=−b−Δ√2aY2=−b+Δ√2a
Δ‾‾√=100‾‾‾‾√=10
Y1=−b−Δ√2a=−(10)−102∗−1=−20−2=+10
Y2=−b+Δ√2a=−(10)+102∗−1=0−2=0
answer:
32
Step-by-step explanation:
Answer: 50° Fahrenheit
Step-by-step explanation:
Here, the equation that shows the temperature of x degree Celsius in Fahrenheit is,

Where x is a variable.
Thus, For the temperature of 10° Celsius,
x = 10° Celsius
The temperature in Fahrenheit is,


Thus, the increasing temperature by 10° C is equivalent to increasing temperature by 50° F.
Answer:

Step-by-step explanation:
Divide n by 100,000.
This gives us the "number of times 100,000 fits in n", or, "how many 100,000's n is", or as the hint says, "how many times larger n is than 100,000".
All represented by this formula:
