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Anastaziya [24]
3 years ago
7

In a chemical reaction between copper metal and silver nitrate, 12.7 g of copper(II) and 64.5 g of silver nitrate react, and 38.

1 g of Silver is produced. 21) Predict the products and write the balanced equation and include the physical state of each. 22) What type of chemical reaction is this? 23) Which is the limiting reactant? You must include the work for this to receive full credit. 24) What mass of excess is used up, and what mass is left over? 25) Calculate the percent yield.
Chemistry
1 answer:
hodyreva [135]3 years ago
8 0

Answer:What should you do if you realize during research that your original theory is wrong

Explanation:

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Using the thermodynamic information in the ALEKS Data tab, calculate the boiling point of titanium tetrachloride . Round your an
ddd [48]

Answer:

The boiling point is 308.27 K (35.27°C)

Explanation:

The chemical reaction for the boiling of titanium tetrachloride is shown below:

TiCl_{4(l)} ⇒ TiCl_{4(g)}

ΔH°_{f} (TiCl_{4(l)}) = -804.2 kJ/mol

ΔH°_{f} (TiCl_{4(g)}) = -763.2 kJ/mol

Therefore,

ΔH°_{f} = ΔH°_{f} (TiCl_{4(g)}) - ΔH°_{f} (TiCl_{4(l)}) = -763.2 - (-804.2) = 41 kJ/mol = 41000 J/mol

Similarly,

s°(TiCl_{4(l)}) = 221.9 J/(mol*K)

s°(TiCl_{4(g)}) = 354.9 J/(mol*K)

Therefore,

s° = s° (TiCl_{4(g)}) - s°(TiCl_{4(l)}) = 354.9 - 221.9 = 133 J/(mol*K)

Thus, T = ΔH°_{f} /s° = [41000 J/mol]/[133 J/(mol*K)] = 308. 27 K or 35.27°C

Therefore, the boiling point of titanium tetrachloride is 308.27 K or 35.27°C.

5 0
3 years ago
In the equation shown, what are the reactant(s)?
Vladimir [108]
C3H8 + O2 (please give me brainliest$
4 0
2 years ago
Write about an object's motion in your own words.
arlik [135]

Answer:

An objects motion is called kinetic energy.  Which is energy that is cause by movement or motion

Explanation:

8 0
2 years ago
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The solubility of CO2 gas in water increases with increasing temperature. is not dependent on temperature. decreases with decrea
nadya68 [22]
What is the question?
7 0
3 years ago
A sample of seawater weighs 250 g and has a volume of 173 ml. What is the density of seawater?
kari74 [83]

Answer:

<h2>The answer is 1.45 g/mL</h2>

Explanation:

The density of a substance can be found by using the formula

density =  \frac{mass}{volume}  \\

From the question

mass of seawater = 250 g

volume = 173 mL

It's density is

density =  \frac{250}{173}  \\  = 1.4450867052...

We have the final answer as

<h3>1.45 g/mL</h3>

Hope this helps you

8 0
3 years ago
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