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Ludmilka [50]
3 years ago
14

PPLLLZZZ HHEEEELLLPPPP​

Chemistry
1 answer:
masya89 [10]3 years ago
5 0

Answer:

B) Cell Membrane

Explanation:

A) Chloroplasts are NOT in all cells, A is incorrect

C) Centrioles are for cell division, C is not correct

D) Cell walls are NOT in all cells, D is not correct

B) the cell membrane is responsible for materials traveling into and out of the cells to maintain homeostasis

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A mixture of 0.682 mol of H2 and 0.440 mol of Br2 is combined in a reaction vessel with a volume of 2.00 L. At equilibrium at 70
ahrayia [7]

Answer: 0.294 mol of Br_2 present in the reaction vessel.

Explanation:

Initial moles of  H_2 = 0.682 mole

Initial moles of  Br_2 = 0.440 mole

Volume of container = 2.00 L

Initial concentration of H_2=\frac{moles}{volume}=\frac{0.682moles}{2.00L}=0.341M

Initial concentration of Br_2=\frac{moles}{volume}=\frac{0.440moles}{2.00L}=0.220M

equilibrium concentration of H_2=\frac{moles}{volume}=\frac{0.536mole}{2.00L}=0.268M

The given balanced equilibrium reaction is,

                            H_2(g)+Br_2(g)\rightleftharpoons 2HBr(g)

Initial conc.              0.341 M     0.220 M         0  M

At eqm. conc.    (0.341-x) M      (0.220-x) M     (2x) M

The expression for equilibrium constant for this reaction will be,

K_c=\frac{[HBr]^2}{[Br_2]\times [H_2]}

we are given : (0.341-x) = 0.268 M

x= 0.073 M

Thus equilibrium concentration of Br_2 = (0.220-x) M = (0.220-0.073) M = 0.147 M

[Br_2]=\frac{moles}{volume}\\0.147=\frac{xmole}{2.00L}\\\\x=0.294 mole

Thus there are 0.294  mol of Br_2 present in the reaction vessel.

7 0
3 years ago
The taste of acid is sour​
arlik [135]

Answer:

have you tasted acid?

Explanation:

also the taste of salt is sour.

7 0
3 years ago
Read 2 more answers
CO is a primary pollutant.
Anuta_ua [19.1K]

True

Carbon monoxide is a primary pollutant which no odor results from incomplete combustion of fuel. The man sources are gasoline and burning of biomass.

Depending on the source of emission, pollutants can be classified into two groups that is primary and secondary pollutants.

A primary pollutant is emitted in the atmosphere directly from a source. It can be either natural sch as volcanic eruptions, sandstorms or man-made that is due to industrial and vehicle emissions.  Examples of primary pollutants are nitrogen oxides, carbon monoxide and particulate matter.

Secondary pollutant is due to interactions between primary and secondary pollutants. These can be chemical or physical interactions. Examples are photo-chemical oxidants and secondary particulate matter.

Therefore, carbon monoxide CO is a primary pollutant.





7 0
3 years ago
Read 2 more answers
2ch4(g) c2h2(g) 3h2(g) describe what is happening within the system when it is at equilibrium in terms of concentrations, reacti
SashulF [63]

Balanced chemical reaction: 2CH₄(g) ⇄ C₂H₂(g) + 3H₂(g).

1) In a chemical reaction, chemical equilibrium is the state in which both reactants (methane CH₄) and products (ethyne C₂H₂ and hydrogen H₂) are present in concentrations which have no further tendency to change with time.  

2) At equilibrium, both the forward and reverse reactions are still occurring.

3) Reaction rates of the forward and backward reactions are equal and  there are no changes in the concentrations of the reactants and products.

4 0
3 years ago
Read 2 more answers
Determine the energy in joules of a photon whose frequency is 3.55 x10^17 hz
zaharov [31]
The equation for energy of a photon is E=hv where v equals frequency and h equals the Planck constant (6.626X10^-34). So since you've been given frequency you can just plug in frequency to find the total energy in joules.

E=(3.55X10^17)(6.626X10^-34)
E=2.35223X10^-16

Not sure how many significant figures you needed. Hope this helped.


4 0
3 years ago
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