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Soloha48 [4]
3 years ago
13

Which type of front does not move ​

Chemistry
1 answer:
shusha [124]3 years ago
5 0
Stationary Front: a front that is not moving. When a warm or cold front stops moving, it becomes a stationary front.
You might be interested in
Write the cell notation for the voltaic cell that incorporates each of the following redox reactions:(b) Cu²⁺(aq) + SO₂(g) + 2H₂
yawa3891 [41]

The cell notation for the given voltaic cell is

SO₂(g) | SO₄²⁻(aq) || Cu²⁺(aq) | Cu (s)

<h3>What is a voltaic cell?</h3>

A voltaic cell often called a galvanic cell, is a type of electrochemical cell.

It is a combination of two metal rods called electrodes.

A half cell is formed when both electrodes are submerged in a solution containing a particular mix of ions.

The electrolyte is the liquid in which both electrodes are submerged and acts as a salt bridge connecting the half cells.

The cell undergoes a chemical reaction known as a redox reaction.

One of the electrodes serves as an anode and undergoes oxidation, while the other electrode serves as a cathode and undergoes reduction.

To write the cell notation, write the half-reaction of the cells.

At the anode, oxidation occurs

SO_2(g) \longrightarrow SO_4^{2-}(aq) + 4H^+ (aq) + 2e^-

At cathode

Cu^{2+}(aq) + 2e^- \longrightarrow Cu(s)

In the cell notation, the anode is written on the left side, and the cathode is written on the right side. A vertical line differentiates the phases and the double vertical line represents the salt bridge.

The cell notation for the given voltaic cell is

SO₂(g) | SO₄²⁻(aq) || Cu²⁺(aq) | Cu (s)

Learn more about cell notation:

brainly.com/question/17218591

#SPJ4

8 0
1 year ago
Kp for the reaction CO2(g) + C(s) --- 2CO(g) is 1.47 at 727°C. Calculate Kc at this temperature.
Neko [114]

Answer:

The correct answer is "0.0179".

Explanation:

The given reaction is:

⇒ CO_2(g) + C(s) \rightleftharpoons  2 \ CO(g)

The given value is:

At 727°C temperature,

Kp = 1.47

As we know,

Gas constant,

R = 0.0821 L atm/mol.K

Temperature,

= 727+273

= 1000 \ K

Now,

The change in moles will be:

⇒ \Delta n=Products-reactants

⇒       =2-1

⇒       =1

As we know,

⇒  K_p=K_c(RT)^{\Delta n}

On substituting the given values, we get

⇒  1.47=K_c(0.0821\times 1000)^1

⇒    K_c=\frac{1.47}{0.0821\times 1000}

⇒          =\frac{1.47}{82.1}

⇒          =0.0179

8 0
3 years ago
Why are intensive properties useful for identifying a subtenant?
g100num [7]
Because these characteristics do not depend on the amount of sample, nor do they change according to conditions.
8 0
3 years ago
2NH3 → N2 + 3H2 If 2.22 moles of ammonia (NH3) decomposes according to the reaction shown, how many moles of hydrogen (H2) are f
Rashid [163]

Answer:

C

Explanation:

According to the mole ratio, using 2NH3 will give you 3H2. Which means in order to find the moles of H2 you would only need to divide 2 and multiply 3 to get the amount of moles of H2 produced.

7 0
3 years ago
. Given the reaction 2HgO → 2Hg + O2 , how many moles of elemental mercury will be obtained by the decomposition of 1 mole of Hg
AveGali [126]

Answer:

one mole of HgO will give one mole of Hg.

Explanation:

Given data:

Moles of HgO = 1 mol

Moles of Hg = ?

Solution:

Chemical equation:

2HgO → 2Hg + O₂

Now we will compare the moles of Hg with HgO from balance chemical equation.

                  HgO   :     Hg

                    2       :      2

                     1       :      2/2×1 = 1 mol

So, one mole of HgO will give one mole of Hg.

6 0
3 years ago
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