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3 years ago

Think about the decomposition reaction of ozone.

Chemistry

1 answer:

____ [38]3 years ago

3 0

Answer:

3441.6 grams.

Explanation:

2 O₃ → 3 O₂

First we convert 71.7 moles of ozone (O₃) into moles of oxygen gas (O₂), using the stoichiometric coefficients of the reation:

71.7 mol O₃ * $\frac{3molO_2}{2molO_3}$ = 107.55 mol O₂

Then we convert 107.55 moles of O₂ into grams, using the molar mass of O₂:

107.55 mol * 32 g/mol = 3441.6 g

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noname [10]

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3 years ago

When water reacts with potassium metal the hydrogen produced ignites explosively on the surface of water .What cause the ignitio

Julli [10]

Answer:

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Explanation:

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3 years ago

When potassium hydroxide and barium chloride react, potassium chloride and barium hydroxide are formed. The balanced equation fo

Mashcka [7]

Answer:

The answer to your question is letter C.

Explanation:

Reaction

Potassium hydroxide = KOH

Barium chloride = BaCl₂

Potassium chloride = KCl

Barium hydroxide = Ba(OH)₂

KOH + BaCl₂ ⇒ KCl + Ba(OH)₂

Reactant Elements Products

1 K 1

1 Ba 1

2 Cl 1

1 H 2

1 O 2

The reaction is unbalanced

2KOH + BaCl₂ ⇒ 2KCl + Ba(OH)₂

Reactant Elements Products

2 K 2

1 Ba 1

2 Cl 2

2 H 2

2 O 2

Now, the reaction is balanced

7 0

3 years ago

Read 2 more answers

N₂O(g) + 3 H₂(g) N₂H4(1) + H₂O(1) AH = -317 kJ/mol

docker41 [41]

Answer:

Explanation:

Recall that ΔH is the sum of the heats of formation of the products minus the heat of formation of the reactants multiplied by their respective coefficients. That is:

$\displaystyle \Delta H^\circ_{rxn} = \sum \Delta H^\circ_{f} \left(\text{Products}\right) - \sum \Delta H^\circ_{f} \left(\text{Reactants}\right)$

Therefore, from the chemical equation, we have that:

$\displaystyle \begin{aligned} (-317\text{ kJ/mol}) = \left[\Delta H^\circ_f \text{ N$_2$H$_4$} + \Delta H^\circ_f \text{ H$_2$O} \right] -\left[3 \Delta H^\circ_f \text{ H$_2$}+\Delta H^\circ_f \text{ N$_2$O}\right] \end{aligned}$

Remember that the heat of formation of pure elements (e.g. H₂) are zero. Substitute in known values and solve for hydrazine:

$\displaystyle \begin{aligned} (-317\text{ kJ/mol}) & = \left[ \Delta H^\circ _f \text{ N$_2$H$_4$} + (-285.8\text{ kJ/mol})\right] -\left[ 3(0) + (82.1\text{ kJ/mol})\right] \\ \\ \Delta H^\circ _f \text{ N$_2$H$_4$} & = (-317 + 285.8 + 82.1)\text{ kJ/mol} \\ \\ & = 50.9\text{ kJ/mol} \end{aligned}$

In conclusion, our answer is A.

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2 years ago

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Yuliya22 [10]

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