Think about the decomposition reaction of ozone.
1 answer:
Answer:
3441.6 grams.
Explanation:
2 O₃ → 3 O₂
First we <u>convert 71.7 moles of ozone (O₃) into moles of oxygen gas (O₂)</u>, using the <em>stoichiometric coefficients</em> of the reation:
71.7 mol O₃ * = 107.55 mol O₂
Then we <u>convert 107.55 moles of O₂ into grams</u>, using the <em>molar mass of O₂</em>:
107.55 mol * 32 g/mol = 3441.6 g
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Answer : The molar mass of the unknown gas will be 79.7 g/mol
Explanation : To solve this question we can use graham's law;
Now we can use nitrogen as the gas number 2, which travels faster than gas 1;
So, 167 / 99 = 1.687 So the nitrogen gas is 1.687 times faster that the unknown gas 1
We can compare the rates of both the gases;
So here, Rate of gas 2 / Rate of gas 1 =
Now, 1.687 = square root [ ]
When we square both the sides we get;
2.845 = (molar mass 1) / (28.01 g/mol N2)
On rearranging, we get,
2.845 X (28.01 g/mol N2) = Molar mass 1
So the molar mass of unknown gas will be = 79.7 g/mol