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Lilit [14]
3 years ago
7

Think about the decomposition reaction of ozone.

Chemistry
1 answer:
____ [38]3 years ago
3 0

Answer:

3441.6 grams.

Explanation:

2 O₃ → 3 O₂

First we <u>convert 71.7 moles of ozone (O₃) into moles of oxygen gas (O₂)</u>, using the <em>stoichiometric coefficients</em> of the reation:

71.7 mol O₃ * \frac{3molO_2}{2molO_3} = 107.55 mol O₂

Then we <u>convert 107.55 moles of O₂ into grams</u>, using the <em>molar mass of O₂</em>:

107.55 mol * 32 g/mol = 3441.6 g

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4 0
3 years ago
When water reacts with potassium metal the hydrogen produced ignites explosively on the surface of water .What cause the ignitio
Julli [10]

Answer:

Pottasium reacts with water vigorously and the reation is exothermic. The heat released causes the hydrogen released to ignite

Explanation:

7 0
3 years ago
When potassium hydroxide and barium chloride react, potassium chloride and barium hydroxide are formed. The balanced equation fo
Mashcka [7]

Answer:

The answer to your question is letter C.

Explanation:

Reaction

Potassium hydroxide = KOH

Barium chloride = BaCl₂

Potassium chloride = KCl

Barium hydroxide = Ba(OH)₂

           KOH   +   BaCl₂    ⇒    KCl   +   Ba(OH)₂

         Reactant        Elements       Products

               1                     K                      1

               1                     Ba                    1

               2                    Cl                     1  

                1                     H                    2

                1                     O                    2

The reaction is unbalanced

        2KOH   +   BaCl₂    ⇒   2KCl   +   Ba(OH)₂

         Reactant        Elements       Products

               2                     K                     2

               1                     Ba                    1

               2                    Cl                     2  

               2                      H                    2

               2                     O                    2

Now, the reaction is balanced

7 0
3 years ago
Read 2 more answers
N₂O(g) + 3 H₂(g) N₂H4(1) + H₂O(1) AH = -317 kJ/mol
docker41 [41]

Answer:

A

Explanation:

Recall that Δ<em>H</em> is the sum of the heats of formation of the products minus the heat of formation of the reactants multiplied by their respective coefficients. That is:


\displaystyle \Delta H^\circ_{rxn} = \sum \Delta H^\circ_{f} \left(\text{Products}\right) - \sum \Delta H^\circ_{f} \left(\text{Reactants}\right)

Therefore, from the chemical equation, we have that:


\displaystyle \begin{aligned} (-317\text{ kJ/mol}) = \left[\Delta H^\circ_f \text{ N$_2$H$_4$} +  \Delta H^\circ_f \text{ H$_2$O}  \right]   -\left[3 \Delta H^\circ_f \text{ H$_2$}+\Delta H^\circ_f \text{ N$_2$O}\right] \end{aligned}

Remember that the heat of formation of pure elements (e.g. H₂) are zero. Substitute in known values and solve for hydrazine:

\displaystyle \begin{aligned} (-317\text{ kJ/mol}) & = \left[ \Delta H^\circ _f \text{ N$_2$H$_4$} + (-285.8\text{ kJ/mol})\right] -\left[ 3(0) + (82.1\text{ kJ/mol})\right] \\ \\ \Delta H^\circ _f \text{ N$_2$H$_4$} & = (-317 + 285.8 + 82.1)\text{ kJ/mol} \\ \\ & = 50.9\text{ kJ/mol} \end{aligned}

In conclusion, our answer is A.

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