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Lilit [14]
3 years ago
7

Think about the decomposition reaction of ozone.

Chemistry
1 answer:
____ [38]3 years ago
3 0

Answer:

3441.6 grams.

Explanation:

2 O₃ → 3 O₂

First we <u>convert 71.7 moles of ozone (O₃) into moles of oxygen gas (O₂)</u>, using the <em>stoichiometric coefficients</em> of the reation:

71.7 mol O₃ * \frac{3molO_2}{2molO_3} = 107.55 mol O₂

Then we <u>convert 107.55 moles of O₂ into grams</u>, using the <em>molar mass of O₂</em>:

107.55 mol * 32 g/mol = 3441.6 g

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Which postulate of Dalton's atomic model was later changed and why?
telo118 [61]

Answer:

Explanation:

Part two of Dalton's theory had to be modified after mass spectrometry experiments demonstrated that atoms of the same element can have different masses because the number of neutrons can vary for different isotopes of the same element. ... Scientists have even developed the technology to see the world on an atomic level!

hoped i helped you :)

4 0
2 years ago
Darin skateboarded to the north at 4 m/s. In 5 seconds, he sped up to 7 m/s. What was his acceleration?
Julli [10]
To solve this problem we can use following equation.

v =u + at

Where v is the final velocity (m/s), u is the initial velocity (m/s), a is the acceleration (m/s²) and t is the time taken (s).

v = 7 m/s
u = 4 m/s
a = ?
t = 5 s

By applying the equation, we can get
    7 m/s = 4 m/s + a x 5 s
    3 m/s = a x 5 s
          a = 0.6 m/s²

Hence, the acceleration is 0.6 m/s² towards north.

Answer is "C".
4 0
3 years ago
Adding heat to a liquid which of the following. Physical changes
natali 33 [55]
What? Is there choices?
5 0
3 years ago
A(n)____is the smallest particle of an element that has the chemical properties of that element.
AnnyKZ [126]

Answer:

Atom

Explanation:

8 0
3 years ago
If 2.03 g of oxygen react with carbon monoxide, how many grams of CO2 are formed?
mamaluj [8]

Answer:

The suitable equation for this reaction is

2CO + O₂ -----> 2CO₂

Here, we are given that we have 2 grams of O₂

From the equation, we can see that 2 * Moles of O₂ = Moles of CO₂

Moles of O₂:

2/32 = 1/16 moles

Therefore, the number of moles of CO₂ is twice the moles of O₂

Moles of CO₂ = 2 * 1/16

Moles of CO₂  formed = 1/8 moles

Mass of CO₂  formed = Molar mass of CO₂ * Moles of CO₂

Mass of CO₂  formed = 44 * 1/8

Mass of CO₂  formed = 5.5 grams

Hence, option B is correct

Kindly Mark Brainliest, Thanks!!!

8 0
3 years ago
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