Based on the fact that he added three correct questions, Levi is wrong in assuming that the ratio of correct answers to total answers remained the same.
<h3>Why is Levi wrong?</h3><h3 />
When the total number of variables being compared in a ratio changes, the ratio itself will change.
This means that Levi is wrong in assuming that the ratio of correct answers to total questions will remain the same after he added 3 questions to both measures.
The first ratio of correct answers to questions was:
8 : 10
4 : 5
After three correct answers are added, it becomes:
11 : 13
This is not the same as the first ratio of 4 : 5.
Find out more on ratios at brainly.com/question/17429159
#SPJ1
We know that According to Algebra of Real Functions :
If f and g are two real functions which are defined under the same domain then 
Now we need find the Domain of this Function :
The Condition for Square Root to be defined is any Expression under it should be Greater than or Equal to Zero.
When Function is a Fraction, it Cannot be defined when the denominator becomes zero. Because when the denominator is zero, the fraction tends to ∞ (because anything divided by zero tends to ∞)
According to Above Conditions Described above, The Given Function is Definable only when the Expression which is under the Square Root is Greater than Zero and x ≠ 0
⇒ 3x - 9 > 0
⇒ 3x > 9
⇒ x > 3
⇒ The Domain of the Given Function is (3 , ∞)
1st Option is the Answer
The answer is 1782.15 dollars after 2 years
Answer:
Yes
Step-by-step explanation:
The central limit theorem says that If a random variable X from a population has mean u and finite variance σ² , then the sampling distribution of the sample mean X~ approaches a normal distribution with mean u and variance σ²/n as the sample size n approaches infinity.
It is interesting to note that we have neither assumed that the distribution of X is continuous nor we have said anything about the shape of the distribution , whereas the limiting distribution of X is continuous and normal. Thus the distribution of the sample means regardless of the shape of the population having a finite variance , is approximately normal with mean u and variance σ²/n .
Therefore
(standard deviation/ √sample size)²= variance / n
2/ √20
= 2/4.472
=0.44721
The sampling distribution of X` is therefore approximately normal with mean ux=u and σx =σ/n
