Exercise 2:
1 answer:
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Molecular Formula of Propanoic Acid is....
C₃H₆O₂
Where;
Atomic Mass of C = 12
Atomic Mass of H = 1
Atomic Mass of O = 6
Substituting Atomic Masses in molecular formula,
(12)₃ + (1)₆ + (16)₂
36 + 6 + 32
74 g/mol
Result:
Molecular Mass of Propanoic Acid is 74 g/mol. Structure of Methyl Ethanoate and Propanoic Acid are as follow,
C₃H₆O₂
Where;
Atomic Mass of C = 12
Atomic Mass of H = 1
Atomic Mass of O = 6
Substituting Atomic Masses in molecular formula,
(12)₃ + (1)₆ + (16)₂
36 + 6 + 32
74 g/mol
Result:
Molecular Mass of Propanoic Acid is 74 g/mol. Structure of Methyl Ethanoate and Propanoic Acid are as follow,
Answer:
Explanation:
If percentage are given then we are taking total mass is 100 grams.So, the mass of each element is equal to the percentage given.
Mass of Mg = 10.89 g
Mass of Cl = 31.77 g
Mass of O = 57.34 g
Step 1 : convert given masses into moles.
Moles of Mg=
Moles of Cl =
Moles of O =
Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.
For Mg =
For Cl =
For O=
The ratio of Mg :Cl : O= 1 : 2 : 8
Hence the empirical formula is