Ask question

Ask question

All categories

2 years ago

8

The local craft fair charges the vendors a flat rate of $15 plus $10 for each hour that they spend at the fair. If the vendor ow

ed $65, how many hours did he remain at the craft fair?

1 answer:

bearhunter [10]2 years ago

8 0

Answer:

Step-by-step explanation:

10h+15=65 subtract 15 from each side

10h=50, divide each side by 10

h=5

He was at the fair for 5 hours

You might be interested in

Is there an error in this statement If x2 = 25, then x = 5.

katen-ka-za [31]

Yes there is an error in this statement.

because x^2 = 25
so x = 5...this is one condition

Another condition is x = -5
(-5)^2 = 25 (this is also true)

7 0

3 years ago

Read 2 more answers

The equation 2x2 − 12x + 1 = 0 is being rewritten in vertex form. Fill in the missing step. Given 2x2 − 12x + 1 = 0 Step 1 2(x2

Bezzdna [24]

Answer:

Part 1) $2(x-3)^{2}-17=0$ (the missing steps in the explanation)

Part 3) (8, 4); The vertex represents the maximum profit

Part 4) x = 3.58, 0.42

Part 5) x = 6, x = 44; The zeros represent the number of monthly memberships where no profit is made

Part 6) 2(x − 7)2 + 118; x = $7

Part 7) The maximum height of the puck is 4 feet. −(x − 4)^2 + 6

Part 8) (x + 3)^2 − 4

Part 9) 2(x − 1)^2 = 4

Part 10) 8(x − 4)^2 + 592

Step-by-step explanation:

Part 1) we have

$2x^{2} -12x+1=0$

Convert to vertex form

step 1

Factor the leading coefficient and complete the square

$2(x^{2} -6x)+1=0$

$2(x^{2} -6x+9)+1-18=0$

step 2

$2(x^{2} -6x+9)+1-18=0$

$2(x^{2} -6x+9)-17=0$

step 3

Rewrite as perfect squares

$2(x-3)^{2}-17=0$

Part 3) we have

$f(x)=-x^{2}+16x-60$

we know that

This is the equation of a vertical parabola open downward

The vertex is a maximum

Convert to vertex form

$f(x)+60=-x^{2}+16x$

Factor the leading coefficient

$f(x)+60=-(x^{2}-16x)$

Complete the squares

$f(x)+60-64=-(x^{2}-16x+64)$

$f(x)-4=-(x^{2}-16x+64)$

Rewrite as perfect squares

$f(x)-4=-(x-8)^{2}$

$f(x)=-(x-8)^{2}+4$

The vertex is the point (8,4)

The vertex represent the maximum profit

Part 4) Solve for x

we have

$-2(x-2)^{2}+5=0$

$-2(x-2)^{2}=-5$

$(x-2)^{2}=2.5$

square root both sides

$(x-2)=(+/-)1.58$

$x=2(+/-)1.58$

$x=2(+)1.58=3.58$

$x=2(-)1.58=0.42$

Part 5) we have

$f(x)=-x^{2}+50x-264$

we know that

The zeros or x-intercepts are the value of x when the value of the function is equal to zero

so

In this context the zeros represent the number of monthly memberships where no profit is made

To find the zeros equate the function to zero

$-x^{2}+50x-264=0$

$-x^{2}+50x=264$

Factor -1 of the leading coefficient

$-(x^{2}-50x)=264$

Complete the squares

$-(x^{2}-50x+625)=264-625$

$-(x^{2}-50x+625)=-361$

$(x^{2}-50x+625)=361$

Rewrite as perfect squares

$(x-25)^{2}=361$

square root both sides

$(x-25)=(+/-)19$

$x=25(+/-)19$

$x=25(+)19=44$

$x=25(-)19=6$

Part 6) we have

$-2x^{2}+28x+20$

This is a vertical parabola open downward

The vertex is a maximum

Convert the equation into vertex form

Factor the leading coefficient

$-2(x^{2}-14x)+20$

Complete the square

$-2(x^{2}-14x+49)+20+98$

$-2(x^{2}-14x+49)+118$

Rewrite as perfect square

$-2(x-7)^{2}+118$

The vertex is the point (7,118)

therefore

The video game price that produces the highest weekly profit is x=$7

Part 7) we have

$f(x)=-x^{2}+8x-10$

Convert to vertex form

$f(x)+10=-x^{2}+8x$

Factor -1 the leading coefficient

$f(x)+10=-(x^{2}-8x)$

Complete the square

$f(x)+10-16=-(x^{2}-8x+16)$

$f(x)-6=-(x^{2}-8x+16)$

Rewrite as perfect square

$f(x)-6=-(x-4)^{2}$

$f(x)=-(x-4)^{2}+6$

The vertex is the point (4,6)

therefore

The maximum height of the puck is 4 feet.

Part 8) we have

$x^{2}+6x+5$

Convert to vertex form

Group terms

$(x^{2}+6x)+5$

Complete the square

$(x^{2}+6x+9)+5-9$

$(x^{2}+6x+9)-4$

Rewrite as perfect squares

$(x+3)^{2}-4$

Part 9) we have

$2x^{2}-4x-2=0$

This is the equation of a vertical parabola open upward

The vertex is a minimum

Convert to vertex form

Factor 2 the leading coefficient

$2(x^{2}-2x)-2=0$

Complete the square

$2(x^{2}-2x+1)-2-2=0$

$2(x^{2}-2x+1)-4=0$

Rewrite as perfect squares

$2(x-1)^{2}-4=0$

$2(x-1)^{2}=4$

The vertex is the point (1,-4)

Part 10) we have

$8x^{2}-64x+720$

This is the equation of a vertical parabola open upward

The vertex is a minimum

Convert to vertex form

Factor 8 the leading coefficient

$8(x^{2}-8x)+720$

Complete the square

$8(x^{2}-8x+16)+720-128$

$8(x^{2}-8x+16)+592$

Rewrite as perfect squares

$8(x-4)^{2}+592$

the vertex is the point (4,592)

The population has a minimum at x=4 years ( that is after 4 years since 1998 )

6 0

2 years ago

Seattle, Washington is known for being very rainy. One day last month, 8 inches of rain fell in 1 1/2 hours. What is the rate of

Leno4ka [110]

Answer:

0.44ft/hr

Step-by-step explanation:

Given parameters:

Quantity of rainfall = 8inches

1ft = 12inches

so;

$\frac{8}{12}$ = 0.67ft

Time = $\frac{3}{2}$ hr

Unknown:

Rate of rainfall expressed in ft/hr = ?

Solution:

The rate of the rainfall is given as;

Rate = $\frac{Quantity}{time}$

Rate = $\frac{0.67ft}{\frac{3}{2} }$ = 0.44ft/hr

8 0

3 years ago

Read 2 more answers

Brandon has a garden in his backyard. He picked 66 tomatoes from 6 tomato plants. What is the ratio of tomato plants to tomatoes

Makovka662 [10]

The answer is 1:11. After it being simplified from 6:66. Hope this helps.

4 0

3 years ago

Read 2 more answers

Joe is at the ice cream shop, and his house is 10 blocks north of the shop. The park is 10 blocks south of the ice cream shop. W

Furkat [3]

Answer:

The distance between the ice cream shop and Joe's house is the same as the distance between the ice cream shop and the park. So Joe is not closer to the park or his house, he is in the middle.

Step-by-step explanation:

We consider that the ice cream shop is the zero value in the number line. We assume that going north is positive (right side of the number line) and going south is negative (left side of the number line).

The house position is 10 block north of the ice cream shop, so it is represented by the integer 10.

The park is 10 blocks south of the ice cream shop, so it is represented by the integer -10.

The lower absolute value of the integer, the closer position from the ice cream shop.

If we calculate the absollute value of the House position:

|10|=10

Then, we calculate the the absollute value of the Parkposition

|-10|=10

In conclusion, the distance between the ice cream shop and Joe's house is the same as the distance between the ice cream shop and the park. Joe is in the middle.

5 0

2 years ago