Answer:
1 Mole O₂ / 2 Mole H₂O
Explanation:
The balance chemical equation for the synthesis of water is as follow,
2 H₂ + O₂ → 2 H₂O
In this equation the moles are specified by the coefficients i.e.
2 moles of H₂ reacting with 1 mole of O₂
2 moles of H₂ producing 2 moles of H₂O
1 mole of O₂ producing 2 moles of H₂O
Hence the molar ratio for O₂ and H₂O can be written as,
1 Mole O₂ : 2 Mole H₂O
or,
1 Mole O₂ / 2 Mole H₂O
Answer:
There is 1.6 L of NO produced.
Explanation:
I assume you have an excess of NH3 so that O2 is the limiting reagent.
<u>Step 1:</u> Data given
2.0 liters of oxygen reacts with ammonia
<u>Step 2:</u> The balanced equation
4NH3 + 5O2 → 4NO + 6H2O
For 4 moles of NH3, we need 5 moles of O2 to produce 4 moles of NO and 6 moles of H2O
Consider all gases are kept under the same conditions for pressure and temperature, we can express this mole ratio in terms of the volumes occupied by each gas.
This means: when the reaction consumes 4 liters of ammonia (and 5 liters of oxygen) it produces 4 liters of nitrogen monoxide
Now, when there is 2.0 liters of oxygen consumed, there is 4/2.5 = 1.6 L of nitrogen monoxide produced.
There is 1.6 L of NO produced.
Your answer would be, Sugar is the solute, and water is the solvent. a solution is the mixture of two, or more substances.
Hope that helps!!!
Answer:
21 g of N₂ are produced by the decomposition
Explanation:
The reaction is: 2 NaN3 → 2 Na + 3 N2
2 moles of sodium nitride decompose in order to produce 2 moles of Na and 3 moles of nitrogen gas.
According to stoichiometry, ratio is 2:3. Therefore we say,
2 moles of nitride can produce 3 moles of N₂
Then, 0.5 moles of NaN₃ will produce (0.5 . 3) / 2 = 0.75 moles of N₂
We convert the moles to mass, to find the answer
0.75 mol . 28 g / 1 mol = 21 g
