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Firlakuza [10]
2 years ago
12

6. If 0.500 mol NaN3 react, what mass in grams of nitrogen will result?

Chemistry
1 answer:
lions [1.4K]2 years ago
7 0

Answer:

21 g of N₂ are produced by the decomposition

Explanation:

The reaction is: 2 NaN3 → 2 Na + 3 N2

2 moles of sodium nitride decompose in order to produce 2 moles of Na and 3 moles of nitrogen gas.

According to stoichiometry, ratio is 2:3. Therefore we say,

2 moles of nitride can produce 3 moles of N₂

Then, 0.5 moles of NaN₃ will produce (0.5 . 3) / 2 = 0.75 moles of N₂

We convert the moles to mass, to find the answer

0.75 mol . 28 g / 1 mol = 21 g

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Answer:

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Explanation:

Step 1: Data given

Mass of the weak acid = 1.168 grams

volume of NaOH = 28.75 mL = 0.02875 L

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Since we only know 1 equivalence point, we suppose the acid is monoprotic

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Moles NaOH = molarity NaOH * volume NaOH

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