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jeyben [28]
3 years ago
13

Determine whether the vectors u and v are parallel, orthogonal, or neither.

Mathematics
2 answers:
bezimeni [28]3 years ago
6 0

The given vectors are and

Two vectors are said to be orthogonal if they are perpendicular to each other. i.e. the dot product of the two vectors is zero.

Let us consider the dot product of the vectors

. == which is not equal to zero. Hence, the given vectors are not orthogonal.

Two vectors are said to be parallel if one vector is a scalar multiple of the other vector.

Here we can observe that the from the given vectors, one vector can not be expressed as the scalar multiple of the other vector.

Hence, the given vectors are neither parallel nor orthogonal.

Gnom [1K]3 years ago
3 0

Answer:

Neither

Step-by-step explanation:

Given: The given vectors areu=  and v=.

To find: To find whether the vectors u and v are parallel, orthogonal, or neither

Solution: Two vectors are said to be orthogonal if they are perpendicular to each other that is the dot product of the two vectors is zero.

Let us consider the dot product of the vectors

u{\cdot}v={\cdot}

u{\cdot}v=

u{\cdot}v=

which is not equal to zero.

Hence, the given vectors are not orthogonal.

Two vectors are said to be parallel if one vector is a scalar multiple of the other vector.

In the given vectors, it can be observed that , one vector can not be expressed as the scalar multiple of the other vector.

Hence, the given vectors are neither parallel nor orthogonal.

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Okay this my last one can y'all help
zlopas [31]

a. The solution is (0,2)

b. The first expression will be easier to substitute as in the first expression the variable y is already isolated on one side of the equation so we can easily put 5x+2 in place of y in equation 2.

Step-by-step explanation:

Given equations are:

y = 5x+2\ \ \ \ Eqn1\\12.5x+2.5y = 5\ \ \ \ Eqn2

a. Solution

Putting y = 5x+2 in equation 2

12.5x+2.5(5x+2) = 5\\12.5x+12.5x+5 = 5\\25x +5 = 5\\25x = 5-5\\25x = 0\\x = 0

Putting x = 0 in equation 1

y = 5(0)+2\\= 0+2 = 2

Hence,

The solution is (0,2)

b: Reason:

The first expression will be easier to substitute as in the first expression the variable y is already isolated on one side of the equation so we can easily put 5x+2 in place of y in equation 2.

Keywords: Linear equation, substitution

Learn more about linear equations at:

  • brainly.com/question/4786449
  • brainly.com/question/4793866

#LearnwithBrainly

7 0
4 years ago
explain how comparison tangent of 45 and 738 is different from comparing 645 and 649 and how to draw that
antoniya [11.8K]
45 is different fro 738 just subtract
8 0
4 years ago
Find the points at which the graph of 2x^2+2y^2- 20x +12y +3 = 0 has a vertical and horizontal tangent
____ [38]

Compute the derivative d<em>y</em>/d<em>x</em> and check where it is zero (for horizontal tangents) or undefined (for vertical tangents).

2<em>x</em>² + 2<em>y</em>² - 20<em>x</em> + 12<em>y</em> + 3 = 0

d/d<em>x</em> [2<em>x</em>² + 2<em>y</em>² - 20<em>x</em> + 12<em>y</em> + 3] = 0

4<em>x</em> + 4<em>y</em> d<em>y</em>/d<em>x</em> - 20 + 12 d<em>y</em>/d<em>x</em> = 0

(4<em>y</em> + 12) d<em>y</em>/d<em>x</em> = 20 - 4<em>x</em>

(<em>y</em> + 3) d<em>y</em>/d<em>x</em> = 5 - <em>x</em>

d<em>y</em>/d<em>x</em> = (5 - <em>x</em>) / (<em>y</em> + 3)

• Horizontal tangents:

d<em>y</em>/d<em>x</em> = 0   →   5 - <em>x</em> = 0   →   <em>x</em> = 5

Solve for <em>y</em> when <em>x</em> = 5 :

2•5² + 2<em>y</em>² - 20•5 + 12<em>y</em> + 3 = 0

2<em>y</em>² + 12<em>y</em> - 47 = 0

<em>y</em> = (-6 ± √(130))/2

So there are two horizontal tangents at the points

(5, (-6 - √(130))/2) and (5, (-6 + √(130))/2)

• Vertical tangents:

1/(d<em>y</em>/d<em>x</em>) = 0   →   <em>y</em> + 3 = 0   →   <em>y</em> = -3

Solve for <em>x</em> when <em>y</em> = -3 :

2<em>x</em>² + 2•(-3)² - 20<em>x</em> + 12•(-3) + 3 = 0

2<em>x</em>² - 20<em>x</em> - 15 = 0

<em>x</em> = (10 ± √(130))/2

So there are two vertical tangents at the points

((10 - √(130))/2, -3) and ((10 + √(130))/2, -3)

Alternatively, you can complete the square to identify the equation of a circle:

2<em>x</em>² + 2<em>y</em>² - 20<em>x</em> + 12<em>y</em> + 3 = 0

2 (<em>x</em>² - 10<em>x</em>) + 2 (<em>y</em>² + 6<em>y</em>) = -3

2 (<em>x</em>² - 10<em>x</em> + 25 - 25) + 2 (<em>y</em>² + 6<em>y</em> + 9 - 9) = -3

2 (<em>x</em> - 5)² - 50 + 2 (<em>y</em> + 3)² - 18 = -3

2 (<em>x</em> - 5)² + 2 (<em>y</em> + 3)² = 65

(<em>x</em> - 5)² + (<em>y</em> + 3)² = 65/2

which is a circle centered at (5, -3) with radius √(65/2). The horizontal tangents occur at the points where the <em>x</em> term vanishes (<em>x</em> = 5), and the vertical ones where <em>y</em> vanishes (<em>y</em> = -3).

6 0
3 years ago
Mrs. Searl is sewing a pair of pants and a shirt. The pants require 138 yards of fabric. The shirt requires 114 yards of fabric.
avanturin [10]

252 is the answer

total amount=the whole amount

total amount =amount of pants+amount of shirts

total amount=138+114

total amount=252

Answer=252

8 0
3 years ago
Is -5 a rational or an irrational number​
Ahat [919]

Answer:

Rational

Step-by-step explanation:

An irrational number cannot be written as the ratio. of two integers. An irrational number is simply the opposite of a rational number. (Recall that a rational number is one that can be represented as the ratio of two integers.

A rational number is one that can be written as an integer over an integer, with non-zero denominator. ie. all your fractions.

An irrational number cannot be expressed as a ratio of integers

-5 is rational because it is a number that ends and is not a decimal that doesnt terminate.

3 0
3 years ago
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