The sales tax rate is 10% if Andrew buys a toy rocket price at 29 how much tax will she pay

Use the given graph to determine the limit, if it exists. A coordinate graph is shown with a horizontal line crossing the y axis

Lesechka [4]

Answer:

The limit of the function does not exists.

Step-by-step explanation:

From the graph it is noticed that the value of the function is 6 from all values of x which are less than 2. At x=2, the line y=6 has open circle. It means x=2 is not included.

For x<2

$f(x)=6$

The value of the function is -3 from all values of x which are greater than 2. At x=2, the line y=-3 has open circle. It means x=2 is not included.

For x>2

$f(x)=-3$

The value of y is 1 at x=2, because of he close circles on (2,1).

For x=2

$f(x)=1$

Therefore the graph represents a piecewise function, which is defined as

$f(x)=\begin{cases}6& \text{ if } x2 \end{cases}$

The limit of a function exist at a point a if the left hand limit and right hand limit are equal.

$lim_{x\rightarrow a^-}f(x)=lim_{x\rightarrow a^+}f(x)$

The function is broken at x=2, therefore we have to find the left and right hand limit at x=2.

$lim_{x\rightarrow 2^-}f(x)=6$

$lim_{x\rightarrow 2^+}f(x)=-3$

$6\neq-3$

Since the left hand limit and right hand limit are not equal therefore the limit of the function does not exists.

6 0

3 years ago

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Sarah biked 13 miles south from her house to the library. Then she turned and biked 10 miles

Tanya [424]

Answer:

16.40

Step-by-step explanation:

use Pythagorean theorem

4 0

3 years ago

Please help!!! the graph of F(x), shown below, has the same shape as the graph of G(x)=x^3, but it shifted down 1 unit. what is

rusak2 [61]

One unit down means a change in the y-axis. The graph one unit above shows no y-intercept in the equation because the intercept is 0.

6 0

3 years ago

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What is the radius of a circle whose equation is x2 y2 8x – 6y 21 = 0?

andrew11 [14]

we know that

the standard form of the equation of the circle is

$(x-h)^{2} +(y-k)^{2}=r^{2}$

where

(h,k) is the center of the circle

r is the radius of the circle

In this problem we have

$x^{2} +y^{2} +8x-6y+21=0$

<u>Convert to standard form</u>

Group terms that contain the same variable, and move the constant to the opposite side of the equation

$(x^{2}+8x) +(y^{2}-6y)=-21$

Complete the square twice. Remember to balance the equation by adding the same constants to each side.

$(x^{2}+8x+16) +(y^{2}-6y+9)=-21+16+9$

$(x^{2}+8x+16) +(y^{2}-6y+9)=4$

Rewrite as perfect squares

$(x+4)^{2} +(y-3)^{2}=4$

$(x+4)^{2} +(y-3)^{2}=2^{2}$

the center of the circle is $(-4,3)$

the radius of the circle is $2\ units$

therefore

<u>the answer is</u>

the radius of the circle is $2\ units$

8 0

3 years ago

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Write an equation of the line with slope -1 passing through (8,5).

True [87]

Answer:

y = -1x + 13

Step-by-step explanation:

y = -1x + b

5 = -1(8) + b

5 = -8 + b

13 = b

8 0

3 years ago

The sales tax rate is 10% if Andrew buys a toy rocket price at 29 how much tax will she pay​

The sales tax rate is 10% if Andrew buys a toy rocket price at 29 how much tax will she pay