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DIA [1.3K]
2 years ago
8

Which of following words mean addition? Check all that apply.

Mathematics
2 answers:
Molodets [167]2 years ago
7 0
Plus, add, altogether, increased by
olga2289 [7]2 years ago
7 0

Answer:

A, D, E,

Step-by-step explanation:

mark me brainiest

pls and ty

hope this helps!

<em>QUEENOFTARUS </em>

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There are 16 girls I a school club. The number of girls is 4 more than twice the number of boys. Find the number of boys.
olga_2 [115]

6 boys

16-4=12

12/2=6

It's not that hard of a problem you just have to read in-between the lines

5 0
3 years ago
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If the ratio of side lengths of similar polygons is 6:11, what is the ratio of perimeters
algol13

Answer:

6 : 11

Step-by-step explanation:

the ratio 6 : 11 applies to all linear measure in the similar polygons

Both side lengths and perimeter are linear, hence

ratio of both is 6 : 11

8 0
2 years ago
What is the volume of a cylindrical bucket that is 35 cm tall and has a base with a diameter of 21 cm? Use pi= 22/7 and round yo
Natali [406]
The volume of a cylinder is given by the multiplication of the area of the base by the height of the cylinder.  π×r²(area of the base) × h (height of the cylinder) ⇔
\frac{22}{7}×(\frac{21}{2} )^{2}cm²×35cm=12127.5cm³
(r is half of the diameter. Because we are doing the square of r, the cm also are squared.)
Rounding to the nearest tenth is to round the result so that it maintains a number after the point - the result is 12127.5cm³
6 0
2 years ago
Read 2 more answers
Health insurance benefits vary by the size of the company (the Henry J. Kaiser Family Foundation website, June 23, 2016). The sa
xxMikexx [17]

Answer:

\chi^2 = \frac{(32-42)^2}{42}+\frac{(18-8)^2}{8}+\frac{(68-63)^2}{63}+\frac{(7-12)^2}{12}+\frac{(89-84)^2}{84}+\frac{(11-16)^2}{16}=19.221

Now we can calculate the degrees of freedom for the statistic given by:

df=(rows-1)(cols-1)=(3-1)(2-1)=2

And we can calculate the p value given by:

p_v = P(\chi^2_{2} >19.221)=0.000067

And we can find the p value using the following excel code:

"=1-CHISQ.DIST(19.221,2,TRUE)"

Since the p values is higher than a significance level for example \alpha=0.05, we can reject the null hypothesis at 5% of significance, and we can conclude that the two variables are dependent at 5% of significance.

Step-by-step explanation:

Previous concepts

A chi-square goodness of fit test "determines if a sample data matches a population".

A chi-square test for independence "compares two variables in a contingency table to see if they are related. In a more general sense, it tests to see whether distributions of categorical variables differ from each another".

Solution to the problem

Assume the following dataset:

Size Company/ Heal. Ins.   Yes   No  Total

Small                                      32   18    50

Medium                                 68     7    75

Large                                     89    11    100

_____________________________________

Total                                     189    36   225

We need to conduct a chi square test in order to check the following hypothesis:

H0: independence between heath insurance coverage and size of the company

H1:  NO independence between heath insurance coverage and size of the company

The statistic to check the hypothesis is given by:

\sum_{i=1}^n \frac{(O_i -E_i)^2}{E_i}

The table given represent the observed values, we just need to calculate the expected values with the following formula E_i = \frac{total col * total row}{grand total}

And the calculations are given by:

E_{1} =\frac{50*189}{225}=42

E_{2} =\frac{50*36}{225}=8

E_{3} =\frac{75*189}{225}=63

E_{4} =\frac{75*36}{225}=12

E_{5} =\frac{100*189}{225}=84

E_{6} =\frac{100*36}{225}=16

And the expected values are given by:

Size Company/ Heal. Ins.   Yes   No  Total

Small                                      42    8    50

Medium                                 63     12    75

Large                                     84    16    100

_____________________________________

Total                                     189    36   225

And now we can calculate the statistic:

\chi^2 = \frac{(32-42)^2}{42}+\frac{(18-8)^2}{8}+\frac{(68-63)^2}{63}+\frac{(7-12)^2}{12}+\frac{(89-84)^2}{84}+\frac{(11-16)^2}{16}=19.221

Now we can calculate the degrees of freedom for the statistic given by:

df=(rows-1)(cols-1)=(3-1)(2-1)=2

And we can calculate the p value given by:

p_v = P(\chi^2_{2} >19.221)=0.000067

And we can find the p value using the following excel code:

"=1-CHISQ.DIST(19.221,2,TRUE)"

Since the p values is higher than a significance level for example \alpha=0.05, we can reject the null hypothesis at 5% of significance, and we can conclude that the two variables are dependent at 5% of significance.

3 0
3 years ago
Find the interior and exterior angles of regular triangle.
storchak [24]

Answer:

dhbsugubihsvhukejbduisxkgdbwq

Step-by-step explanation:

iwdyhbjksgcsbhhsnnsgdhhsns

4 0
2 years ago
Read 2 more answers
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