0.1875 mol of Na2CO3 needed to react with the 750 mL of 0.250 M H2SO4.
The given reaction between Na2CO3 and H2SO4 are already balanced.
Na2CO3 + H2SO4 → Na2SO4 + CO2.H2O
First, let us determine the number of moles of H2SO4.
Molarity (mol/L) = number of moles of H2SO4 / volume of H2SO4
0.250 M = number of moles of H2SO4 / [(750 mL)(1 L/1000 mL)]
number of moles of H2SO4 = 0.1875 mol
Then, let us determine the number of moles of Na2CO3 that would react with 0.1875 mol H2SO4.
number of moles of Na2CO3 = moles of H2SO4 * stoichiometric ratio
number of moles of Na2CO3 = 0.1875 mol H2SO4 * (1 mol Na2CO3/ mol H2SO4)
number of moles of Na2CO3 = 0.1875 mol Na2CO3
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The weight on Earth is 686 newtons and its weight on Jupiter is 1617 newtons.
Answer:
9.09
Explanation:
Please kindly check attachment for the step by step solution of the given problem.
The answer is a. H+ and H2O. For a half-reaction in acidic solutions, elements that are not hydrogen and oxygen are balanced first. Then we add H2O to balance oxygen atoms and we add H+ to balance the hydrogen atoms. We do the same steps for basic solutions, but we also add hydroxide ions OH- in the latter part.
Answer:
valance electrons
Explanation:
these are the electrons in the outermost shell
