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sp2606 [1]
3 years ago
13

I need help asap :>

Physics
1 answer:
Lena [83]3 years ago
5 0

Answer:

\huge\boxed{\sf v = 0.75\ m / s}

Explanation:

<u>Given Data:</u>

Wavelength = λ = 0.25 m

Frequency = f = 3 Hz

<u>Required:</u>

Speed = v = ?

<u>Formula:</u>

v = fλ

<u>Solution:</u>

v = (3)(0.25)

v = 0.75 m / sec

\rule[225]{225}{2}

Hope this helped!

<h3>~AH1807</h3>
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if you push a box a distance of 2000 meters with a force of 1 newton, how many calories have you used
kap26 [50]
Note that
1 J = 0.239 cal

By definition,
Work = Force x Distance

Therefore work done is
W = (1 N)*(2000 m) = 2000 J

In calories,
W = (2000 J)*(0.239 cal/J) = 478 cal

Answer: 478 calories

4 0
3 years ago
Two 6.7 kg bodies, A and B, collide. The velocities before the collision are and . After the collision, . What are (a) the x-com
Law Incorporation [45]

Question:

Two 6.7 kg bodies, A and B, collide. The velocities before the collision are 40i+37j and 19 i +3.7 j . After the collision 9.8 i + 5.1 j, 50 i+35.6 j . What are (a) the x-component and (b) the y-component of the final velocity of B? (c) What is the change in the total kinetic energy (including sign)?

Answer:

(a) 50 m/s

(b) 35.6 m/s

(c) -735.16 J

Explanation:

Given,

u_A=40i+37j=\sqrt{40^2+37^2}=54.5 m/s

u_B=19 i +3.7 j=\sqrt{19^2+3.7^2}=19.4m/s

v_A=9.8 i + 5.1 j=\sqrt{9.8^2+5.1^2}=11m/s

v_B=50 i+35.6 j=\sqrt{50^2+35.6^2}=61.4m/s

Change in kinetic energy = final kinetic energy - initial kinetic energy

\Delta K.E.=\frac{1}{2} m(v_A+v_B)^2 -\frac{1}{2} m(u_A+u_B)^2\\

\Delta K.E.=\frac{1}{2} 6.7(11+61.4)^2 -\frac{1}{2} 6.7(54.5+19.4)^2\\\Delta K.E. =17559.89-18295.05\\\Delta K.E. = -735.16 J

7 0
3 years ago
What is the mass of air in a room
Karo-lina-s [1.5K]

Answer:

Just do 1000 times 1.8

Explanation:

This is a good answer

7 0
3 years ago
A scientist views an unknown cell under a microscope. Which of the following observations would support the claim that it is a p
alisha [4.7K]

Answer:

Explanation:

Sorry I can’t give you an exact answer, but it is it is either A or D hope this helps!

5 0
4 years ago
Read 2 more answers
Which motor and body should Devon use to build the car with the greatest acceleration?
PilotLPTM [1.2K]

<u>Complete Question:</u>

Devon has several toy car bodies and motors. The motors have the same mass, but they provide different amounts of force, as shown in this table.  

The bodies have the masses shown in this table (refer attached figure).  

Which motor and body should Devon use to build the car with the greatest acceleration?

motor 1, with body 1

motor 1, with body 2

motor 2, with body 1

motor 2, with body 2

<u>Answer:</u>

Devon should build the car with motor 2 and body 1 for having the greatest acceleration.

<u>Explanation:</u>

As per Newton's second law of motion, the acceleration of any object is directly proportional to the force on the object and inversely proportional to the mass of the object.

It can be seen that motor 2 has greater force than the force provided by motor 1. Similarly, the mass of body 1 is found to be lesser compared to mass of body 2. So,

          acceleration =\frac{\text { Force }}{\text { mass }}

It gives, the system with motor 2 and body 1 the maximum acceleration. So the car should be built with motor 2 and body 1.

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3 years ago
Read 2 more answers
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