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crimeas [40]
2 years ago
7

Help!!I'm not sure my answer is correct.The problem is attached!​

Physics
1 answer:
oksian1 [2.3K]2 years ago
7 0

Answer:

where's ur answer?

Explanation:

hihi

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Which is the best example of tropism in plants?
seraphim [82]

Answer:

Here are some examples of tropism in plants : Sunflowers are one of the best examples of positive phototropism , as they always grow facing the sun.

Explanation:

Although some experts consider that perhaps such a clear growth movement should not be considered tropism.

3 0
2 years ago
For copper, ρ = 8.93 g/cm3 and M = 63.5 g/mol. Assuming one free electron per copper atom, what is the drift velocity of electro
viktelen [127]

Answer:

V_d = 1.75 × 10⁻⁴ m/s

Explanation:

Given:

Density of copper, ρ = 8.93 g/cm³

mass, M = 63.5 g/mol

Radius of wire = 0.625 mm

Current, I = 3A

Area of the wire, A = \frac{\pi d^2}{4} = A = \frac{\pi 0.625^2}{4}

Now,

The current density, J is given as

J=\frac{I}{A}=\frac{3}{ \frac{\pi 0.625^2}{4}}= 2444619.925 A/mm²

now, the electron density, n = \frac{\rho}{M}N_A

where,

N_A=Avogadro's Number

n = \frac{8.93}{63.5}(6.2\times 10^{23})=8.719\times 10^{28}\ electrons/m^3

Now,

the drift velocity, V_d

V_d=\frac{J}{ne}

where,

e = charge on electron = 1.6 × 10⁻¹⁹ C

thus,

V_d=\frac{2444619.925}{8.719\times 10^{28}\times (1.6\times 10^{-19})e} = 1.75 × 10⁻⁴ m/s

4 0
3 years ago
Read 2 more answers
With the simplified model of the eye, what corrective lens (specified by focal length as measured in air) would be needed to ena
Ymorist [56]

Answer:

Please see the attached picture for the complete answer.

Explanation:

6 0
3 years ago
A ball is dropped off the balcony of a hotel room and it takes 2.8s to fall to the ground . how high above the ground is the bal
RideAnS [48]

The height of the ball above the ground is 38.45 m

First we will calculate the velocity of the ball when it touch the ground by using first equation of motion

v=u+gt

v=0+9.81×2.8

v=27.468 m/s

now the height of the ground can be calculated by the formula

v=√2gh

27.468=√2×9.81×h

h=38.45 m

5 0
3 years ago
A car started from a rest and accelerated at 9.54 m/s2 for 6.5 seconds. How much distance was covered by the car?
ElenaW [278]

Explanation:

S =ut + 1/2at^2

S = 0×6.5 + (1/2 × 9.54) × 6.5^2

S =0 + 4.77 ×42.25

S=201.5m

5 0
3 years ago
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