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3 years ago

13

4. Lockout/tagout (LOTO) is a safety procedure that ensures dangerous machines are properly shut off and not started up again pr

ior to the completion of maintenance or servicing work?
A) True
b) False

1 answer:

klemol [59]3 years ago

5 0

Answer:true

Explanation:

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What is the purpose of gears?

Brrunno [24]

Answer:

To help wheels move in a circle

Explanation:

6 0

2 years ago

If ceramic vessels are typed together based as they were all used as storage containers, in spite of the fact that design elemen

andriy [413]

If ceramic vessels are typed together based as they were all used as storage containers, in spite of the fact that design elements indicate they are from different time periods, then they have to be functional typeoperational typesystematic type is given below

Explanation:

The Batiscan site, excavated in the 1960s, produced one of the largest Vinette I collections known to date. Revisiting this ceramic assemblage has revealed more heterogeneity than is generally recognized within the Vinette I type of pottery. Indeed, variations from the typological definition exist, both within and between Early Woodland ceramic collections. A number of diagnostic traits, such as the presence of exterior and interior cord impressions and the absence of decoration, are challenged by the present study. It is hypothesized that part of this variability is chronological, and that the vessels from Batiscan were manufactured closer to the end of the Early Woodland period. However, other factors, such as the frequency and scale of production, and the possible exchange and circulation of ceramic containers, must also be taken into account when interpreting Vinette I variability.l

3 0

3 years ago

The rate of heat transfer between a certain electric motor and its surroundings varies with time as , Q with dot on top equals n

tekilochka [14]

Answer:

the required expression is $E_2 - E_1$ = 4[ 1 - $e^{(-0.05t)}$ ]

Explanation:

Given the data in the question;

Q = -0.2[ 1 - $e^(-0.05t)$ ]

ω = 100 rad/s

Torque T = 18 N-m

Electric power input = 2.0 kW

now, form the first law of thermodynamics;

dE/dt = dQ/dt + dw/dt = Q' + w'

dE/dt = Q' + w' ------ let this be equation 1

w' is the net power on the system

w' = $w_{elect$ - $w_{shaft$

$w_{shaft$ = T × ω

we substitute

$w_{shaft$ = 18 × 100

$w_{shaft$ = 1800 W

$w_{shaft$ = 1.8 kW

so

w' = $w_{elect$ - $w_{shaft$

w' = 2.0 kW - 1.8 kW

w' = 0.2 kW

hence, from equation 1, dE/dt = Q' + w'

we substitute

dE/dt = -0.2[ 1 - $e^{(-0.05t)$ ] + 0.2

dE/dt = -0.2 + 0.2 $e^{(-0.05t)$ ] + 0.2

dE/dt = 0.2 $e^{(-0.05t)$

Now, the change in total energy, increment E, as a function of time;

ΔE = $\int\limits^t_0}\frac{dE}{dt} . dt$

ΔE = $\int\limits^t_0} 0.2e^{(-0.05t)} dt$

ΔE = $\int\limits^t_0} \frac{0.2}{-0.05} [e^{(-0.05t)}]^t_0$

$E_2 - E_1$ = 4[ 1 - $e^{(-0.05t)}$ ]

Therefore, the required expression is $E_2 - E_1$ = 4[ 1 - $e^{(-0.05t)}$ ]

5 0

2 years ago

Milestone 1: Write code which asks for a length input until it gets an integer 10 or greater, then creates 2 arrays of this leng

jonny [76]

Answer:

import java.util.Scanner;

import java.lang.Math;

class Main {

public static void main(String[] args) {

int length = 0;

boolean lengthCheck = true;

Scanner scan = new Scanner(System.in);

while (lengthCheck == true)

{

System.out.println("Enter an array length (must be 10 or greater):");

length = scan.nextInt();

if (length >= 10)

{

lengthCheck = false;

}

}

int[] firstArray = new int[length];

int[] secondArray = new int[length];

System.out.print("\nFirst Array: ");

for (int i = 0; i < length; i++)

{

firstArray[i] = (int) (Math.random() * 100) + 1;

System.out.print(firstArray[i] + " ");

}

System.out.print("\n\nSecond Array: ");

for (int i = 0; i < length; i++)

{

secondArray[i] = (int) (Math.random() * 100) + 1;

System.out.print(secondArray[i] + " ");

}

System.out.println("\n");

boolean[] isAdded = new boolean[100];

int[] merge = new int[(firstArray.length + secondArray.length)];

int j=0;

for (int i = 0; i < length; i++)

{

if(!isAdded[firstArray[i] - 1]) {

merge[j] = firstArray[i];

j++;

isAdded[firstArray[i] - 1] = true;

}

if(!isAdded[secondArray[i] - 1]) {

merge[j] = secondArray[i];

j++;

isAdded[secondArray[i] - 1] = true;

}

}

System.out.print("Merged Array: ");

for (int i = 0; i < 2*length && merge[i] != 0; i++)

{

System.out.print(merge[i] + " ");

}

System.out.println("\n");

}

}

3 0

3 years ago

What should Kimi have done to ensure that she was acting legally and ethically?

Mila [183]

Answer:

Kimi have done to ensure that she was acting legally and ethically by following the measure that are discussed below in detail.

Explanation:

Legal measures are those measures that are outlined in regulatory laws. Ethical measures are based on the human postulates of morality and wrongdoing. The distinctions between them are these: Legal measures are based on transcribed law, while ethical measures are based on human rights and violations.

8 0

3 years ago