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Vikki [24]
3 years ago
6

A defense company working for the government claims that at most 6% of its missiles are defective. A sample of 160 missiles is t

aken and 16 are defective. Test their claim at 1% level.
Required:
State clearly the null and the alternative hypothesis
Mathematics
1 answer:
vitfil [10]3 years ago
3 0

Answer:

Null Hypothesis: H0: Defective defense missiles not more than 6%

Alternate hypothesis: Ha: Defective defense missiles are greater than 6%

Step-by-step explanation:

The null hypothesis is the problem statement and the alternate hypothesis is a contradiction of null hypothesis

Hence,

Null Hypothesis: H0: Defective defense missiles not more than 6%

Alternate hypothesis: Ha: Defective defense missiles are greater than 6%

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gtnhenbr [62]

Answer:

97.27 yd²

Step-by-step explanation:

First let's find the area of the right triangle on the left side. To do that, multiply 6x5, then divide the product by 2, since a right triangle is half a rectangle.

6x5=30

30/2=15

Area of triangle=15 yd²

Find area of the middle rectangle. So multiply the length by the width.

9x6=54

Area of rectangle=54 yd²

Find area of the half circle. Formula for area of circle is A=\pi r^{2}. Pi is about 3.14, and radius (r) is 3. Radius is half of the diameter of circle, and the 6 on the left says the diameter of circle.

\pix3^{2}≈28.27

Area of circle is about 28.27 yd²

Add up the three areas.

15+54+28.27=97.27

3 0
3 years ago
Read 2 more answers
On three examinations, you have grades of 85, 78, and 84. There is still a final examination, which counts as one grade In order
Greeley [361]

Answer:

  • It's not possible to earn an A in the course
  • I must have a 73 or MORE to earn a B in the course

Step-by-step explanation:

The average obtained at the end of the course will be:

\frac{85+78+84+x}{4} = av

Where x is the grade obtained in the final examination and av is the final average. To obtain an A, av has to be at least 90, av≥90, and to obtain an B, av has to be at least 80, av≥80

  • Is an A in the course possible?

So, if we get 100 on the final average:

x = 100,

av = (85+78+84+100)/4 = 86,75 and  86,75∠90.

<em>Answer: No, the higher grade obtained would be 86,75.</em>

  • What grade you must have in the final to earn a B in the course

To earn a B, av≥80:

av= \frac{85+78+84+x}{4 \ }\geq  80\\ \frac{247+x}{4}\geq80   \\247+x\geq 80*4\\ x\geq 320-247\\ x\geq 73

<em>Answer: I must have a 73 or MORE to earn a B in the course</em>

6 0
3 years ago
For a good that is a luxury, demand a. tends to be inelastic. b. tends to be elastic. c. has unit elasticity. d. cannot be repre
Readme [11.4K]

Answer:

<h3>I do not know what some of the words mean but I believe it is c</h3><h3 />

Step-by-step explanation:

8 0
3 years ago
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Please help me! I'm spending 50 points on this question and my last two questions never even got answered!
Verdich [7]

Answer:

C.

Step-by-step explanation:

Domain is only affected if certain values can make the result something that either doesn't make sense or is an error. In your situation, it wants you to find the domain of f/g, which is a fraction. The only rule we have for fractions regarding domain is that we simply can't divide by zero, to find the domain for any fraction with variables in the denominator, what I do is take the denominator, set it equal to 0, and solve for x.

So, if we're taking f/g, we have:

\frac{3x^2 + x^4 + 2}{4x - 3}

4x - 3 makes up our denominator, the bottom part of the fraction. So

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4x = 3

x = 3/4

So the denominator is equal to zero when x is equal to 3/4. This would produce an error in any calculator because you can't divide by zero. The domain here is all real numbers except for 3/4.

(For future problems, the only thing to look out for is if your numerator, the top part of the fraction, factors into something that cancels with the bottom. In that case, it wouldn't affect domain because you aren't actually dividing by anything. For example:

\frac{x^2 - 4}{x-2}

If we factor the top, we see that x^2 - 4 = (x - 2)(x + 2). In this case, we have (x - 2) in both the top and bottom of the fraction, so it cancels out, and from there nothing else is restricting our domain. It would be all real numbers in a case like that.)

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Answer:

A. -7 - 7 = -14

B. 7 - 7 = 0

C. -7 - (-7) = 0

D. 7 - (-7) = 14

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