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2 years ago

Triple a number, minus the sum of the number and six

Mathematics

2 answers:

9966 [12]2 years ago

6 0

$\large \mathfrak{Solution : }$

let the number be x

According to above statement :

3x - (x + 6)

3x - x - 6

2x - 6

Over [174]2 years ago

5 0

Answer:

2x-6

Step-by-step explanation:

the number:x

3x-(x+6)

3x-x-6

2x-6

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2 years ago

Jonathan collects postcards and stamps. The number of postcards in his collection is 12 more than 3/4 the number of stamps. He h

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1 year ago

In how many ways can 4 people sit down in 6 seats in a row

Wewaii [24]

Answer:

360

Step-by-step explanation:

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2 years ago

31q=93 what is the value of q

valentina_108 [34]

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2 years ago

A statistics textbook chapter contains 60 exercises, 6 of which are essay questions. A student is assigned 10 problems. (a) What

Scilla [17]

Answer:

a) P=0.3174

b) P=0.4232

c) P=0.2594

d) The shape of the hypergeometric, in this case, is like a binomial with mean np=1.

Step-by-step explanation:

The appropiate distribution to model this is the hypergeometric distribution:

$P(X=x)=\frac{\binom{s}{x}\binom{N-s}{M-x}}{\binom{N}{M}}=\frac{\binom{6}{x}\binom{54}{10-x}}{\binom{60}{10}}$

a) What is the probability that none of the questions are essay?

$P(X=0)=\frac{\binom{6}{0}\binom{54}{10-0}}{\binom{60}{10}}\\\\P(X=0)=\frac{1*(54!/(10!*44!)}{60!/(10!*50!)} =\frac{2.3931*10^{10}}{7.5394*10^{10}} = 0.3174$

b) What is the probability that at least one is essay?

$P(X=1)=\frac{\binom{6}{1}\binom{54}{9}}{\binom{60}{10}}\\\\P(X=1)=\frac{6*(54!/(9!*43!)}{60!/(10!*50!)} =\frac{3.1908*10^{10}}{7.5394*10^{10}} =0.4232$

c) What is the probability that two or more are essay?

$P(X\geq2)=1-(P(0)+P(1))=1-(0.3174+0.4232)=1-0.7406=0.2594$

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3 years ago