All categories

3 years ago

How to Factor 3x^2-x-10

Mathematics

1 answer:

adoni [48]3 years ago

5 0

Solution

( − 2)(3 + 5)

Step-by-step solution:

Use the sum-product pattern

3x^2−−10

3^2+5−6x−10

Common factor from the two pairs

3^2+5−6−10

(3+5)−2(3+5)

Rewrite in factored form

(3+5)−2(3+5)

(−2)(3+5

hope this was good! <3

You might be interested in

A student receives his grade report from a local community college, but the GPA is smudged. He took the following classes: a 2 h

Olin [163]

Answer:

C. 3.0

Step-by-step explanation:

Lets calculate the points:

Art - 2 hrs - B (3) ⇒ 2*3 = 6 points
History - 3 hrs - A (4) ⇒ 3*4 = 12 points
Science - 4 hrs - C (2) ⇒ 4*2 = 8 points
Math - 3 hrs - B (3) ⇒ 3*3 = 9 points
Lab - 1 hr - A (4) ⇒ 1*4 = 4 points

Totals

Total hours = 13
Total points = 39

GPA = total points/ total hours

GPA = 39/13 = 3.0

Correct option is C

3 0

3 years ago

What is the equation of this graphed line?

pantera1 [17]

Answer:

y = - $\frac{1}{3}$ x - 5

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Calculate m using the slope formula

m = (y₂ - y₁ ) / (x₂ - x₁ )

with (x₁, y₁ ) = (- 6, - 3) and (x₂, y₂ ) = (6, - 7)

m = $\frac{-7+3}{6+6}$ = $\frac{-4}{12}$ = - $\frac{1}{3}$

Note the line crosses the y- axis at (0, - 5) ⇒ c = - 5

y = - $\frac{1}{3}$ x - 5 ← equation of line

4 0

3 years ago

7 1/2 pints = _____ quarts

k0ka [10]

7 1/2 pints into quarts is 3.75

4 0

3 years ago

Read 2 more answers

17 mm 8 mm 9 mm 15 mm

OleMash [197]

Answer:

do you have to add the numbers together or multiply

4 0

3 years ago

Read 2 more answers

Solve y=f(x) for x. Then find the input when the output is -3.

DochEvi [55]

Answer:

Please check the explanation

Step-by-step explanation:

Given the function

$f\left(x\right)\:=\:\left(x-5\right)^3-1$

Given that the output = -3

i.e. y = -3

now substituting the value y=-3 and solve for x to determine the input 'x'

$\:\:y=\:\left(x-5\right)^3-1$

$-3\:=\:\left(x-5\right)^3-1\:\:\:$

switch sides

$\left(x-5\right)^3-1=-3$

Add 1 to both sides

$\left(x-5\right)^3-1+1=-3+1$

$\left(x-5\right)^3=-2$

$\mathrm{For\:}g^3\left(x\right)=f\left(a\right)\mathrm{\:the\:solutions\:are\:}g\left(x\right)=\sqrt[3]{f\left(a\right)},\:\sqrt[3]{f\left(a\right)}\frac{-1-\sqrt{3}i}{2},\:\sqrt[3]{f\left(a\right)}\frac{-1+\sqrt{3}i}{2}$

Thus, the input values are:

$x=-\sqrt[3]{2}+5,\:x=\frac{\sqrt[3]{2}\left(1+5\cdot \:2^{\frac{2}{3}}\right)}{2}-i\frac{\sqrt[3]{2}\sqrt{3}}{2},\:x=\frac{\sqrt[3]{2}\left(1+5\cdot \:2^{\frac{2}{3}}\right)}{2}+i\frac{\sqrt[3]{2}\sqrt{3}}{2}$

And the real input is:

$x=-\sqrt[3]{2}+5$

$x=3.74$

4 0

3 years ago