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3 years ago

12

NEED HELP NOW ETHANHUNT 25 POINTS WILL MARK BRAINLIEST!! For the independent reading all you have to do is pick a grade six book

that you have read plz help! 3 photos below

1 answer:

garik1379 [7]3 years ago

7 0

Can you please stop pasting this question, just go to his profile and ask him.

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1) When you hold your nose and go underwater, you can still hear sounds that are made above the water, in the air, if they are l

Deffense [45]

Answer:

Vibrations

Explanation:

That is why when under water it sounds muffled and you cannot hear clearly.

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2 years ago

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During science class Billy used litmus paper to determine the pH of an unknown liquid. The blue litmus paper turned red but ther

lys-0071 [83]

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3 years ago

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A cube of metal has a mass of 11 grams and a volume of 1 cm . When fully submerged in water this metal cube hanging from an accu

Anarel [89]

Answer:

0.098 N

Explanation:

From the question,

Spring scale reading = W-U............... Equation 1

Where W = weight of the cube, U = upthrust.

W = mg

Where m = mass of the cube, g = acceleration due to gravity.

Given: m = 11 g = 0.011 kg, g = 9.8 m/s².

W = 0.011(9.8)

W = 0.1078 N.

From Archimedes principle,

Upthrust = weight of water displaced.

U = (Density of water×volume of metal cube)×acceleration due to gravity.

U = (D×V)g

Given: D = 1000 kg/m², V = 1 cm³ = (1/1000000) = 1×10⁻⁶ m³, g - 9.8 m/s²

U = 1000(9.8)(10⁻⁶)

U = 0.0098 N.

Substitute the value of W and U into equation 1

Reading of the spring scale = 0.1078-0.0098

Reading of the spring scale = 0.098 N

7 0

4 years ago

Mary’s mass is 57 kg and Elizabeth’s weight is 624 N. Each one carries a 9 kg box to the library. Who has the greater normal for

stepan [7]

Elizabeth, weight formula is 624 divided by 9.8 which is greater than 57kg

5 0

3 years ago

A drag racer crosses the finish line doing 212 mi/h and promptly deploys her drag chute. (A.) what force must the drag chute exe

Svet_ta [14]

initial speed of the racer is given as

$v_i = 212 mi/h$

$v_i = 212*\frac{1609}{3600} = 94.75 m/s$

after applied force the final speed is given as

$v_f = 45 mi/h$

$v_f = 45 * \frac{1609}{3600} = 20.11 m/s$

now during this speed change the racer will cover total distance 185 m

so here we will use kinematics

$v_f^2 - v_i^2 = 2 a d$

$20.11^2 - 94.75^2 = 2*a*185$

$a = -23.2 m/s^2$

now the force that chute will exert on the racer will be given as

$F = ma$

$F = 898* 23.2$

$F = 2.1* 10^4 N$

B) here following is the strategy for solving it

1. first we used kinematics to find the acceleration of the car

2. then we used Newton's II law (F = ma) to find the force

4 0

3 years ago