Answer:
A. Constructive
B. Destructive
C. Destructive
D. Constructive
Explanation:
Constructive interference takes place at locations along the path of two superposed waves where the waves are in phase such that a high or low point of one of the waves corresponds with a high or low point of the other wave which gives a resulting wave amplitude which is the sum of the amplitudes of the individual waves
Destructive interference takes place at locations along the path of two superposed waves where one wave is out of phase with the other wave such that a high or low point of one of the waves coincides with a low or high point of the other wave respectively thereby cancelling the effect of the other wave and giving a resulting wave that has an amplitude which is the difference in the amplitudes of the individual waves
Therefore;
At point A, the peak of each wave partially coincides resulting in constructive interference
At point B, the peak of the blue wave and the trough of the red wave partially coincides resulting in destructive interference
At point C, the through of the blue wave and the peak of the back wave partially coincides resulting in destructive interference
At point D, the trough of each wave partially coincides resulting in constructive interference.
Answer:
<em>The initial speed of the sprinter was 2.2 m/s</em>
Explanation:
<u>Constant Acceleration Motion</u>
It's a type of motion in which the velocity of an object changes by an equal amount in every equal period of time.
The following relation applies:

Where a is the constant acceleration, vo the initial speed, vf the final speed, and t the time.
The sprinter speeds up from an unknown initial speed to vf=3 m/s in t=2 seconds with an acceleration of
.
To find the initial speed, we solve the equation for vo:

Substituting the values:



The initial speed of the sprinter was 2.2 m/s
The combined momentum of the passengers is 5000 kgm/s.
<h3>Combined momentum of the passenger</h3>
The combined momentum of the passengers is calculated as follows;
P = mv1 + mv2
where;
- m is mass of the passengers
- v1 is velocity of the first passenger
- v2 is velocity of the second passenger
P = m(v1 + v2)
P = 5000(-1 + 2)
P = 5000 kgm/s
Thus, the combined momentum of the passengers is 5000 kgm/s.
Learn more about momentum here: brainly.com/question/7538238
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If the acceleration constant..
you can use the formula s = ut + 1/2at²
Known that :
s = ?
u = 0
t = 2s
a = 10ms-²
Then you can apply the formula
s = ut + 1/2at²
s = 0 + 1/2(10)(2)²
s = 5 × 4
s = 20m
Answer : 20m
Explanation :
The gravity can be 9,8 or 10. Also im not sure how people teach you but in my school, if the ball goes down the gravity is positive and not negative thats why i put 10ms-² and not -10ms-²
s = displacement/distance
u = initial speed
a = acceleration
t = time
sorry if im wrong
The upward force of the chain on the diamond would be the tension in the chain, and this tension would have to support the weight of the 45g that hangs from the chain.
mass = 45 g = 45/1000 kg = 0.045kg
Weight = mg = 0.045 * 10 ≈ 0.45N, g ≈ 10 m/s²
<span>So the upward force is ≈ </span><span>0.45N. </span>