1: always rearrange the equation to y = mx + c so....
x - y = o
x = y
So the gradient is 1 and it intersects the y axis at (0,0)
The three points could be (1,1), (2,2), (3,3) and so on
2: -x -2y = -10
Multiply everything by -1
x + 2y = 10
2y = 10 - x
y = 5 - x/2
The y intercept is 5 so you could use the point (0,5), (2,4), (4,3) and so on
3: x + y = -2
y = -2 - x
The y intercept is -2 so you could use the points (0,-2), (2,-4), (3,-5) and so on
4: -3y =-x -7
Multiply everything by -1
3y = x + 7
y = x/3 + 7/3
The y intercept is 7/3 so you could use the points (0,7/3), (3,10/3), (6,13/3) and so o
5: -y = -x + 1
y = x - 1
The y intercept is -1 so you could use the points (0,-1), (2,1), (3,2) and so on
Hope this helps! Any questions let me know :)
Answer:
sorry I can't heheh just came to see but it's math you know search on browser one by one I'm sure you can find
20/t=v and 12/t=(v-4) solve both for t
t=20/v and t=12/(v-4) since t=t
20/v=12/(v-4) cross multiplying...
20v-80=12v
8v-80=0
8v=80
v=10mph
The outbound speed was 10mph
Answer:
b
x^0=1
y^-2 =1/y^2
Step-by-step explanation:
2x^0 y^-2
2×1 ×1/3^2
2×1/9
2/9
Answer:
Step-by-step explanation:
34 . since the given two figure are similar their corresponding sides are proportonal.
let the missing side be x
take these ratios
15/18 = x/30
do cross multiplication
18*x = 30*15
18x = 450
x = 450/18
x = 25
therefore missing side is 25
35.since they are also similar their corresponding sides are proportional.
let the missing side be x
for this take these ratios
8/12 = 10/x
do cross multiplication
12*10 = 8*x
120/8 =x
15 =x
therefore missing side is 15.
