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ra1l [238]
3 years ago
5

In the following situation, determine whether you are asked to determine the number of permutations or combinations. Then do the

calculation. How many ways are there to distribute 8 different books among 21 children if no child gets more than one book?
Mathematics
2 answers:
harkovskaia [24]3 years ago
8 0
Permutation is when the order of arrangement matters
Combination is when the order of arrangement does not matter

Distributing 8 different books among 21 children is a combination because the order of arrangement does not matter

The questions is 'how many ways to  pick 8 from 21'

\frac{21!}{(21-8)!8!}= 203490 ways of distributing 8 books among 21 children
Varvara68 [4.7K]3 years ago
4 0

Answer:

BBB

Step-by-step explanation:

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