First factor each number
39=3*13
52=4*13
Now find the greatest common factor, which in our case is 13.
Answer: 13
We need Pythagoras theorem here
a^2+b^2 = c^2
a, b = legs of a right-triangle
c = length of hypotenuse
Let S=shorter leg, in cm, then longer leg=S+2 cm
use Pythagoras theorem
S^2+(S+2)^2 = (10 cm)^2
expand (S+2)^2
S^2 + S^2+4S+4 = 100 cm^2 [collect terms and isolate]
2S^2+4S = 100-4 = 96 cm^2
simplify and form standard form of quadratic
S^2+2S-48=0
Solve by factoring
(S+8)(S-6) = 0 means (S+8)=0, S=-8
or (S-6)=0, S=6
Reject nengative root, so
Shorter leg = 6 cm
Longer leg = 6+2 cm = 8 cm
Hypotenuse (given) = 10 cm
Answer:
y = 2/7 x - 51/7
Step-by-step explanation:
Equation of the line
(y-y1)/(y2-y1) = (x-x1)/(x2-x1)
(y-(-7)/(-9-(-7) = (x-1)/(-6-1)
(y+7)/-2 = (x-1)/-7
(-y-7)/2 = (-x+1)/7
-y-7 = -2/7 x + 2/7
-y = -2/7x +2/7 + 7
y = 2/7 x - 2/7 - 7
y = 2/7 x + (-2-49)/7
y = 2/7 x - 51/7
