<span>4)Increase the mass of both object A and object B.
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Answer:
= 625 nm
Explanation:
We now that for
for maximum intensity(bright fringe) d sinθ=nλ n=0,1,2,....
d= distance between the slits, λ= wavelength of incident ray
for small θ, sinθ≈tanθ= y/D where y is the distance on screen and D is the distance b/w screen and slits.
Given
d=1.19 mm, y=4.97 cm, and, n=10, D=9.47 m
applying formula
λ= (d*y)/(D*n)
putting values we get

on solving we get
= 625 nm
Given that,
Depth of seawater, h = 11,033 m
Density seawater, p (rho) = 1025 kg/m³
Gauge Pressure , P = ??
Since, we know that:
Pressure, P = pgh
Pressure = 1025 * 9.81 * 11033
Pressure = 1109395723.3 N/m²
or
Pressure = 1.1 x 10∧8 Pascal
Answer:
h = 2.5 m
Explanation:
Given that,
Mass of a ball, m = 1.5 kg
Initial velocity of the ball, u = 7 m/s
We need to find the maximum height reached by the ball. Let it is be h. Using the conservation of energy to find it such that,

Put all the values,

So, it will reach to a height of 2.5 m.