Answer:
Net force refers to the sum of all the forces that act upon an object.
Explanation:
Answer:
Explanation:
As we know that Far sighted person has near point shifted to 80 cm distance
so he is able to see the object 80 cm
now the distance of lens from eye is 2 cm
and the person want to see the objects at distance 10 cm
so here the image distance from lens is 80 cm and the object distance from lens is 8 cm
now from lens formula we have
Answer:
The required pressure is 6.4866 atm.
Explanation:
The given data : -
In the afternoon.
Initial pressure of tire ( p₁ ) = 7 atm = 7 * 101.325 Kpa = 709.275 Kpa
Initial temperature ( T₁ ) = 27°C = (27 + 273) K = 300 K
In the morning .
Final temperature ( T₂ ) = 5°C = ( 5 + 273 ) K = 278 K
Given that volume remains constant.
To find final pressure ( p₂ ).
Applying the ideal gas equation.
p * v = m * R * T
= 657.2615 Kpa = 6.486 atm
Answer:
You have to give us an answer choice : )
Answer:
20.6 N
Explanation:
Friction equals normal force times coefficient of friction.
F = Fn μ
On level ground, normal force equal weight.
Fn = W
Therefore:
F = W μ
F = (685 N) (0.0300)
F = 20.6 N