Answer:
a=1.024m/s
t=15.62s
Explanation:
A body that moves with constant acceleration means that it moves in "a uniformly accelerated movement", which means that if the velocity is plotted with respect to time we will find a line and its slope will be the value of the acceleration, it determines how much it changes the speed with respect to time.
When performing a mathematical demonstration, it is found that the equations that define this movement are as follows.
Vf=Vo+a.t (1)
{Vf^{2}-Vo^2}/{2.a} =X (2)
X=Xo+ VoT+0.5at^{2} (3)
X=(Vf+Vo)T/2 (4)
Where
Vf = final speed
Vo = Initial speed
T = time
A = acceleration
X = displacement
In conclusion to solve any problem related to a body that moves with constant acceleration we use the 4 above equations and use algebra to solve
for this problem
Vf=16m/s
Vo=0m/s, the cart starts from the rest
X=125m
we can use the ecuation number tow to calculate the acceleration
{Vf^{2}-Vo^2}/{2.a} =X
{Vf^{2}-Vo^2}/{2.x} =a
{16^{2}-0^2}/{2(125)} =a
a=1.024m/s
to calculate the time we can use the ecuation number 1
Vf=Vo+a.t
t=(Vf-Vo)/a
t=(16-0)/1.024
t=15.62s
1. The problem statement, all variables and given/known data A person jumps from the roof of a house 3.4 meters high. When he strikes the ground below, he bends his knees so that his torso decelerates over an approximate distance of 0.70 meters. If the mass of his torso (excluding legs) is 41 kg. A. Find his velocity just before his feet strike the ground. B. Find the average force exerted on his torso by his legs during deceleration. 2. Relevant equations I can't even seem to figure that part out. Help please? 3. The attempt at a solution I don't know how to start this at all
Answer:
a) 1.67 m/s
b) 23kJ
Explanation:
We need to apply the linear momentum conservation formula, that states:
in this case:
the initital kinetic energy is:
and the final:
The energy lost is given by:
Explanation:
P= rho×g × h (g=10 m/s²) ,
(rho=1000 kg/m³)
P= 1000×10×5= 50,000 N/m² (C)
