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Margarita [4]
3 years ago
6

Two pendulum bobs have equal masses and lengths (8.100 m). bob a is initially held horizontally while bob b hangs vertically at

rest. bob a is released and collides elastically with bob
b. how fast is bob b moving immediately after the collision?
Physics
2 answers:
Karo-lina-s [1.5K]3 years ago
5 0
Since both hv same mass and elsstic collision, so their velocity will exchange. Bob A will stop and bob B will move with speed of A just before the collision.

Speed will be = squreroot ( 2*g*L)

L is length of pendulum
Ira Lisetskai [31]3 years ago
5 0

bob is the bobbiest of them all

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To solve the problem it is necessary to apply the concepts given in the kinematic equations of angular motion that include force, acceleration and work.

Torque in a body is defined as,

\tau_l = F*d

And in angular movement like

\tau_a = I*\alpha

Where,

F= Force

d= Distance

I = Inertia

\alpha = Acceleration Angular

PART A) For the given case we have the torque we have it in component mode, so the component in the X axis is the net for the calculation.

\tau= F*cos(19)*d

On the other hand we have the speed data expressed in RPM, as well

\omega_f = 10rpm = 10\frac{1rev}{1min}(\frac{1min}{60s})(\frac{2\pi rad}{1rev})

\omega_f = 1.0471rad/s

Acceleration can be calculated by

\alpha = \frac{\omega_f}{t}

\alpha = \frac{1.0471}{9}

\alpha = 0.11rad/s^2

In the case of Inertia we know that it is equivalent to

I = \frac{1}{2}mr^2 = \frac{1}{2}(750)*(2.3)^2

I = 1983.75kg.m^2

Matching the two types of torque we have to,

\tau_l=\tau_a

Fd=I\alpha

Fcos(19)*2.3=1983.75(0.11)

F=100.34N

PART B) The work performed would be calculated from the relationship between angular velocity and moment of inertia, that is,

W = \frac{1}{2}I\omega_f^2

W= \frac{1}{2}(1983.75)(1.0471)^2

W=1087.51J

7 0
3 years ago
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djyliett [7]

Answer:

Fourth option

Explanation:

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Hope this helps.

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Answer:

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The corpus callosum is comprised of more than 200 million axons that connect the hemispheres of the brain. Please select the bes
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Hello, love! The answer is True, or T, on Edge2020.

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