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Margarita [4]
4 years ago
6

Two pendulum bobs have equal masses and lengths (8.100 m). bob a is initially held horizontally while bob b hangs vertically at

rest. bob a is released and collides elastically with bob
b. how fast is bob b moving immediately after the collision?
Physics
2 answers:
Karo-lina-s [1.5K]4 years ago
5 0
Since both hv same mass and elsstic collision, so their velocity will exchange. Bob A will stop and bob B will move with speed of A just before the collision.

Speed will be = squreroot ( 2*g*L)

L is length of pendulum
Ira Lisetskai [31]4 years ago
5 0

bob is the bobbiest of them all

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A projectile is fired at ????0=355.0 m/s at an angle of theta=68.4∘ , with respect to the horizontal. Assume that air friction w
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Answer:

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6 0
4 years ago
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shusha [124]

Answer:

R = (-2î − 6ĵ + 10k^)m

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We are given;

D = (2î − 6ĵ)

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Plugging in (2î − 6ĵ) for D in the R equation gives;

(2î − 6ĵ) + R = -5(2î − 6ĵ)j

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(2î − 6ĵ) + R = -10k

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R = (-2î − 6ĵ + 10k^)m

7 0
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