The near point (smallest distance at which an object can be seen clearly) and the far point (the largest distance at which an ob

Question

3 years ago

6

The near point (smallest distance at which an object can be seen clearly) and the far point (the largest distance at which an ob

ject can be seen clearly) are measured for six different people.
near point(cm) far point(cm)
Avishka 40 [infinity]
Berenice 30 300
Chadwick 25 500
Danya 25 [infinity]
Edouard 80 200
Francesca 50 [infinity]

Of the farsighted people, rank them by the power of the lens needed to correct their hyperopic vision. Rank these from largest to smallest power required. To rank items as equivalent, overlap them.

Physics

1 answer:

luda_lava [24] · Answer 1 · 2022-02-08T12:17:10+03:00

Answer:

Edouard > Berenica > Chdwick > Francesca = Avishka = Danya

Explanation:

The near and far vision points for a normal person are

Close view 25 cm

Far vision infinite

Let's use the constructor equation to raise the object to these points

Close vision

1 / f = 1 / o + 1 / i

where f is the focal length, or the distance to the object and i the distance to the image, in this case i must be 25cm for everyone, as this distance is on the same side as the object is negative, according to the optical sign convention

Avishka

The distance to the object is 40 cm

1 / f = 1 / 0.40 - 1 / 0.25 = -1.5

Focal power P is the inverse of the focal length in meters

P = 1 / f = -1.5 D

The vision for the far point is normal and therefore does not require correction P=0

Berenice

Distance to the object that can see o = 0.30 m

1 / f = P = 1 / o + 1 / i

P = 1 / 0.30 -1 / 0.25

P = -0.67 D

Far vision correction