Web 2.0 is a simple static website without any interaction with its users is inaccurate. This statement is accurate in web 1.0 and not 2.0
Further Explanation:
Web 1.0 is considered as the read-only web and represents the 1st implementation of the WWW. It allowed users to look for information online without offering an opportunity to fully interact with its pages. You only got the opportunity to passively read the content and that was it. The pages were static and were sometimes hosted on a free web hosting service.
Web 2.0 offers an interaction with its users. It is the read-write web technology as Berners-Lee would put it and it offers interoperability to its clients. It is what we interact with so much in our day-to-day lives. Examples of web 2.0 are the Wiki, FB, Twitter, and many more. These examples shows us how web 2.0 brings people closer together with information using machines and encourages participation and sharing of information.
Web 3.0 is not commonly used and is known to may as the future web. It is what many refer to as “IOT” or the semantic web. The world is slowly trying to transition into web 3.0 with smart devices trying to connect to the internet. It is trying to alter the web that humans are familiar with into some sort of database. It the web for the foreseeable future.
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<h1> heading </h1> I think
In regards to the rules of compaction, the IPv6 address 2001:0db8:0000:0000:0000:ff00:0012:3456 could also be written as 2001:db8::ff00:12:3456.
<h3>What is IPv6?</h3>
The IPv6 address is known to be a form of Internet Layer protocol made for packet-switched internetworking and it helps to give an end-to-end datagram movement in course of multiple IP networks.
Note that, In regards to the rules of compaction, the IPv6 address 2001:0db8:0000:0000:0000:ff00:0012:3456 could also be written as 2001:db8::ff00:12:3456.
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Answer:
30
Explanation:
Java - Using a method, how do I "write a program whose input is a character and a string, and whose output indicates the number of times the character appears in the string. Your program must define and call the following method that returns the number of times the input character appears in the input string.
public static int countCharacters(char userChar, String userString)"
