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madreJ [45]
3 years ago
13

What is the factored form of the polynomial x2-12x+27

Mathematics
1 answer:
fiasKO [112]3 years ago
8 0

Answer:

(x - 9) + (x + 3)

Step-by-step explanation:

To get the correct answer when factoring the numbers must add up to be the middle variable and multiply together to be the ending original number.

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If you like graphing this is for you :D​
Pavel [41]

Answer:

You are trying to find the x-value when the y-value is 2. On the graph, the x-value is -3 when the y-value is 2. So, the x-value when f(x)=2 is -3.

:)

3 0
2 years ago
What is the length of the curve with parametric equations x = t - cos(t), y = 1 - sin(t) from t = 0 to t = π? (5 points)
zzz [600]

Answer:

B) 4√2

General Formulas and Concepts:

<u>Calculus</u>

Differentiation

  • Derivatives
  • Derivative Notation

Basic Power Rule:

  1. f(x) = cxⁿ
  2. f’(x) = c·nxⁿ⁻¹

Parametric Differentiation

Integration

  • Integrals
  • Definite Integrals
  • Integration Constant C

Arc Length Formula [Parametric]:                                                                         \displaystyle AL = \int\limits^b_a {\sqrt{[x'(t)]^2 + [y(t)]^2}} \, dx

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify</em>

\displaystyle \left \{ {{x = t - cos(t)} \atop {y = 1 - sin(t)}} \right.

Interval [0, π]

<u>Step 2: Find Arc Length</u>

  1. [Parametrics] Differentiate [Basic Power Rule, Trig Differentiation]:         \displaystyle \left \{ {{x' = 1 + sin(t)} \atop {y' = -cos(t)}} \right.
  2. Substitute in variables [Arc Length Formula - Parametric]:                       \displaystyle AL = \int\limits^{\pi}_0 {\sqrt{[1 + sin(t)]^2 + [-cos(t)]^2}} \, dx
  3. [Integrand] Simplify:                                                                                       \displaystyle AL = \int\limits^{\pi}_0 {\sqrt{2[sin(x) + 1]} \, dx
  4. [Integral] Evaluate:                                                                                         \displaystyle AL = \int\limits^{\pi}_0 {\sqrt{2[sin(x) + 1]} \, dx = 4\sqrt{2}

Topic: AP Calculus BC (Calculus I + II)

Unit: Parametric Integration

Book: College Calculus 10e

4 0
3 years ago
The vertex form of the equation of a parabola is y= 3(x - 4)^2 -22. What is the standard form of the equation
Sunny_sXe [5.5K]

Answer:

option A

Step-by-step explanation:

We can find the standard form by expanding the equation:

y = 3(x-4)^2 - 22

y = 3(x^2 - 8x + 16) - 22

y = 3x^2 - 24x + 48 - 22

y= 3x^2 - 24x + 26

So the correct option is option A

8 0
3 years ago
Read 2 more answers
Round 2.794 to the tenths place
viva [34]
2.8

The tenths place is right after the decimal, so when we round 2.794 to the nearest tenths place, we get 2.8

Hope this helps! Have a good day :)
8 0
2 years ago
What is the general equation of a sine function with an amplitude of 6, a period of StartFraction pi Over 4 EndFraction, and a h
Katen [24]

Answer:

C: y = 6 \sin (8(x-\frac{\pi}{2} ))

Step-by-step explanation:

Amplitude is changed by multiplying the entire trig function by a number, by default the amplitude is 1, so multiplying by 6 is necessary; eliminate A and B

Horizontal shift is going through the x axis, so it must be subtracted from the x value. This is only seen in choice C of the remaining answers.

Calculating the period isn't necessary because we already found the right answer but in case you need it in the future; the period is by default 2pi, to get to pi/4, it had to be 8 times smaller, so multiplying x and translations on x by 8 will get you the correct period.

3 0
2 years ago
Read 2 more answers
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