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3 years ago

7.4 code practice question 1 edhesive

Computers and Technology

2 answers:

Semmy [17]3 years ago

4 0

Answer:

7.4 Code Practice: Question 1

def GPAcalc(g):

if g == "a" or g == "A":

return 4

elif g == "B" or g == "b":

return 3

elif g == "C" or g == "c":

return 2

elif g == "D" or g == "d":

return 1

elif g == "F" or g == "f":

return 0

Explanation:

Serhud [2]3 years ago

3 0

Answer:

def GPAcalc(letterG):

if "a" in letterG.lower():

return 4

elif "b" in letterG.lower():

return 3

elif "c" in letterG.lower():

return 2

elif "d" in letterG.lower():

return 1

elif "f" in letterG.lower():

return 0

else:

return("Invalid")

letterGrade = input("Enter your Letter Grade: ")

grade = GPAcalc(letterGrade)

print("Your GPA score is: " + str(grade))

Explanation:

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Write an if-else statement with multiple branches. If givenYear is 2101 or greater, print "Distant future" (without quotes). Els

irga5000 [103]

Answer:

import java.util.Scanner;

public class num9 {

public static void main(String[] args) {

Scanner in = new Scanner(System.in);

System.out.println("Enter year");

int givenYear =in.nextInt();

if(givenYear>=2101){

System.out.println("Distant Future");

}

else if(givenYear>=2001){

System.out.println("21st Century");

}

Explanation:

Using Java programming Language
Import Scanner class to receive user input of the variable givenYear
Use if statement to check the first condition if(givenYear>=2101)
Use else if statement to check the second condition if(givenYear>=2001)
print Distant future and 21st century respectively

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3 years ago