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pickupchik [31]
3 years ago
15

Solve x + 19 = 47. Select one: x = 893 x = 66 x = 28 x = 18

Mathematics
2 answers:
7nadin3 [17]3 years ago
5 0

the answer is 28 hoped that helped

gizmo_the_mogwai [7]3 years ago
4 0

Answer:

x=28 (B)

Step-by-step explanation:

x = 28 (B)

You need to subtract 19 from both sides to get 28.

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I need this answer ASAP please! The rectangle in the figure is composed of six squares. Find the side length of the largest squa
Sladkaya [172]

Answer:

7

Step-by-step explanation:

the side length of the largest square is x

2x-1=3x-8

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3 0
3 years ago
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What is the product of (2x+3) and (4x^2-6x+9)?​
gogolik [260]

Answer:

=8x^3+27

Step-by-step explanation:

First you are going to multply 2x by all of the other numbers in the 2nd parentheses, then do the same with 3. By doing this you should get and answer then combine like terms.

4 0
3 years ago
An athletic field is a 48 yd​-by-96 yd ​rectangle, with a semicircle at each of the short sides. A running track 20 yd wide surr
MA_775_DIABLO [31]

The distance would be equal to 2 times the longest side of the rectangle plus twice the shortest side multiplied by pi / 2 for the semicircle, that is:

longest side 96 and shortest 48

D = 2 * (96) + 2 * (1/2) * pi * 48

D = 192 + pi * 48

This shorter side, which starts at 48, will expand each time by two more in proportion to 20 of the running track between 8 than the number of divisions, that is, 2 * (20/8) = 5

In other words, there are 8 distances, like this:

D1 = 192 + 3.14 * 48 = 342.72 yd

D2 = 192 + 3.14 * (48 + 5) = 358.42 yd

D3 = 192 + 3.14 * (48 + 10) = 374.12 yd

D4 = 192 + 3.14 * (48 + 15) = 389.82 yd

D5 = 192 + 3.14 * (48 + 20) = 405.52 yd

D6 = 192 + 3.14 * (48 + 25) = 421.22 yd

D7 = 192 + 3.14 * (48 + 30) = 436.92 yd

D8 = 192 + 3.14 * (48 + 35) = 452.62 yd

6 0
3 years ago
If the radius of a right circular cylinder is doubled and height becomes 1/4 of the original height, then find the ratio of the
Oduvanchick [21]

<u>Given</u><u> </u><u>info:</u><u>-</u>If the radius of a right circular cylinder is doubled and height becomes 1/4 of the original height.

Find the ratio of the Curved Surface Areas of the new cylinder to that of the original cylinder ?

<u>Explanation</u><u>:</u><u>-</u>

Let the radius of the right circular cylinder be r units

Let the radius of the right circular cylinder be h units

Curved Surface Area of the original right circular cylinder = 2πrh sq.units ----(i)

If the radius of the right circular cylinder is doubled then the radius of the new cylinder = 2r units

The height of the new right circular cylinder

= (1/4)×h units

⇛ h/4 units

Curved Surface Area of the new cylinder

= 2π(2r)(h/4) sq.units

⇛ 4πrh/4 sq.units

⇛ πrh sq.units --------(ii)

The ratio of the Curved Surface Areas of the new cylinder to that of the original cylinder

⇛ πrh : 2πrh

⇛ πrh / 2πrh

⇛ 1/2

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Therefore the ratio = 1:2

The ratio of the Curved Surface Areas of the new cylinder to that of the original cylinder is 1:2

6 0
2 years ago
3x + 4 divided by 2 = 9.5
Sergeu [11.5K]
2.5 is your answer because first we divide the numbers then subtract 2 from both sides and simplify
8 0
2 years ago
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