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4 years ago

Answer fastttt pleaseeee

Mathematics

1 answer:

JulsSmile [24]4 years ago

5 0

The second option 0.110L

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Write the general form of equation (x-8)^2 +(y+2)^2 =1

SpyIntel [72]

(x-h)^2 + (y-k)^2 = r^2
where r is the radius of the circle, 
and h,k are the coordinates of its center;

( x - 8 )^2 + ( y - ( - 2 ) )^2 = 1 ^2 ;
r = 1 ;
h = 8 ; k = - 2.

5 0

3 years ago

What is the difference of 21 15/16 minus 18 3/4 ?

Advocard [28]

$21 \frac{15}{16}-18 \frac{3}{4}=21 \frac{15}{16} - 18 \frac{3 \times 4}{4 \times 4}=21 \frac{15}{16}-18 \frac{12}{16}=\boxed{3 \frac{3}{16}}$

5 0

4 years ago

You have four bills that need to be paid this week . Electric 182.17, water bill 92.55, the cell phone bill 225.82 and the cable

Lorico [155]

200+100+200+100=$600.
Hope this helps and please give brainliest!

6 0

3 years ago

In triangle ABC , side AB is 6 and side AC is 4: Which statement is needed to prove that segment DE is parallel to segment BC an

Andreyy89

Answer:

Segment AD is 3, and segment AE is 2.

Step-by-step explanation:

In a triangle, the line joining the mid points of two sides is parallel and half of the third sides of the triangle.

Here, ABC is a triangle,

In which,

AB = 6,

AC = 4,

D∈ AB and E∈AC

Let DE ║BC,

And, $DE=\frac{1}{2}BC$

In triangles ADE and ABC,

$\angle ADE\cong \angle ABC$ ( Alternative interior angle theorem )

$\angle AED\cong \angle ACB$

By AA similarity postulate,

$\triangle ADE\sim \triangle ABC$

∵ Corresponding sides of similar triangle are in same proportion,

$\implies \frac{AD}{AB}=\frac{AE}{AC}=\frac{DE}{BC}$

$\frac{AD}{AB}=\frac{AE}{AC}=\frac{BC}{2BC}$

$\frac{AD}{AB}=\frac{AE}{AC}=\frac{1}{2}$

$\implies AD = \frac{AB}{2}\text{ and }AE =\frac{AC}{2}$

$\implies AD = \frac{6}{2}=3\text{ and }AE =\frac{4}{2}=2$

Hence, the correct option would be,

Segment AD is 3, and segment AE is 2.

4 0

3 years ago

If x equals 6 what is 5x-(3+9

RSB [31]

I think it is 18 Hope this helps. :)

7 0

3 years ago

Read 2 more answers