Answer:
C. 6 E23 atoms Cl2
Explanation:
S.T.P:
∴ T = 25°C ≅ 298 K
∴ P = 1 atm
ideal gas:
∴ R = 0.082 atm.L/K.mol
∴ V = 22.4 dm³ = 22.4 L
⇒ mol (n) = PV/RT
⇒ n Cl2(g) = ((1 atm)(22.4 L)/(0.082 atm.L/K.mol)(298 K))
⇒ n Cl2(g) = 0.9166 mol
⇒ atoms Cl2(g) = (0.9166 mol)*(6.022 E23 atoms/mol)
⇒ atoms Cl2(g) = 5.52 E23 atoms ≅ 6 E23 atoms
As waves reach the shore, the energy in front of the wave slows down due to friction with the shallow bottom. ... The wave breaks, and it usually does so in water depth that is 1.3 times the wave height.
Answer: There are 0.0637 moles present in 85.0 mL of 0.750 M KOH.
Explanation:
Given: Volume = 85.0 mL (1 mL = 0.001 L) = 0.085 L
Molarity = 0.750 M
It is known that molarity is the number of moles of solute present in liter of a solution.
Therefore, moles present in given solution are calculated as follows.
Thus, we can conclude that there are 0.0637 moles present in 85.0 mL of 0.750 M KOH.
Answer:
T > 1250K
Explanation:
A reaction is thermodynamically favorable when ΔG° is < 0
ΔG° is defined as:
ΔG° = ΔH° - TΔS°
As ΔG° must be < 0:
TΔS° > ΔH°
As ΔHº=+50kJ and ΔSº=+40J/K:
T×40J/K > 50000J
T > 50000J / 40J/K
<em>T > 1250K</em>
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I hope it helps!