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3 years ago

HELPPPPPPP!!! PLEASEEEEE! What is the mean and MAD of the dot plot? Round The mad to the nearest hundreds

Mathematics

2 answers:

Natasha_Volkova [10]3 years ago

4 0

Answer:
Mean- 6
MAD- 1.73...

Explanation:
Mean- I added all the dots together then divided by 15.
MAD- For the mean I got 6 so I subtracted the difference of each dot from 6, added them all up, and divided them by 15.

yawa3891 [41]3 years ago

3 0

Mode: 5,7

Median: 6

Range: 13 - 2 = 11

IQR (interquartile Range): 7 - 5 = 2

Mean: 6

M.A.D (Mean Absolute Deviation): 1.73

________________________________

( how I found the mean )

2 x 1 = 2

3 x 1 = 3

4 x 1 = 4

4 x 5 = 20

6 x 2 = 12

4 x 7 = 28

8 x 1 = 8

13 x 1 = 13

________________________________

2 + 3 + 4 + 20 + 12 + 28 + 8 + 13 = 90/15 = 6!

mean = 6!

____________________________________

(finding the M.A.D mean absolute deviation)

6 - 2 = 4

6 - 3 = 3

6 - 4 = 2

6 - 5 = 1

6 - 6 = 0

6 - 7 = 1

6 - 8 = 2

6 - 13 = 7

_____________________________

1 x 4 = 4

_____________________________

4 + 3 + 2 + 4 + 4 + 2 + 7 = 26/15 = 1.73

so the answer to your question should be 1.73!

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Multiply and give the answer in scientific notation:

kakasveta [241]

Step-by-step explanation:

given

$(1.5 \times {10}^{4} )(8 \times {10}^{8} )$

in order to make multiplication easier we need to change the 1.5 into a whole number form.

thus

$(15 \times {10}^{ - 1} \times {10}^{4} )(8 \times {10}^{8} )$

$= (15 \times {10}^{4 - 1} )(8 \times {10}^{8} )$

First law of indices applied there

=(15×10^3)(8×10^8)

=(15×8)(10^3×10^8)

=120×10^3+8 ( first law of indices, which states that , numbers of the same base multiplying each other, take one of the base and add the exponent. and clearly both 15 and 8 are in base 10

=120×10^11

=1.20×10^2 ×10^11

=1.20×10^11+2

=1.20×10^13

so the answer is alt B

7 0

3 years ago

mr williams is making punch for his class party. the recipe he is using says to mix 3 cups pineapply juice, 7 cups mango juice a

maksim [4K]

Divide 12 by 72. this equals 6. then multiply. 7x6=47 3x6=18 and 5x6=30 there we go!

8 0

3 years ago

Solve for both systems: y+7z=22 and 8y + 7z = 127

7nadin3 [17]

Manipulate the first equation to
y = 22-7z

Then substitute in the second to find z
8(22-7z) + 7z = 127
176-56z+7z = 127
-49z = -49
z = 1

So y = 22-7(1) = 22-7 = 15

y = 15; z = 1

5 0

2 years ago

Read 2 more answers

Given the following sets:

hjlf

<h3>Answer: 10</h3>

===========================================================

Explanation:

Even though your teacher doesn't want you to list the items of the set, it helps to do so.

We'll be working with these two sets

A = {b, d, f, h, j, I, n, p, r, t}

C = {d, h, I, p, t}

When we union them together, we combine the two sets together. Think of it like throwing all the letters in one bin rather than two bins.

A u C = {b, d, f, h, j, I, n, p, r, t, d, h, I, p, t }

The stuff that isn't bolded is set A, while the stuff that is bolded is set C

After we toss out the duplicates, we end up with this

A u C = {b, d, f, h, j, I, n, p, r, t}

But wait, that's just set A. Notice how everything in set C can be found in set A. This indicates set C is a subset of set A.

That's why all of the stuff in bold was tossed out (because they were duplicates of stuff already mentioned).

Once we determine what set A u C looks like, we count out the number of items in that set to determine the final answer.

There are 10 items in {b, d, f, h, j, I, n, p, r, t} which means 10 is the final answer.

----------------------------

An alternative method is to use the formula below

n(A u C) = n(A) + n(C) - n(A and C)

n(A u C) = 10 + 5 - 5

n(A u C) = 10

The notation n(A and C) counts how many items are found in both sets A and C at the same time. But as mentioned earlier, this is identical to just counting how many items are in set C. So we'll have n(C) cancel out with itself.

In short, n(A u C) = n(A) = 10

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2 years ago

I know this question is easy, but I don’t really know how to do it? Help? If possible put a quick explanation, it’s fine if not!

lorasvet [3.4K]

Answer:

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Hope this helps :)

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2 years ago