1.Chemical
2.Physical
3.Physical
4.Chemical
5Physical
I am not sure if these are right, but I hope I helped (:
Answer:
Here not any option is matching but only (A) option is near to our answer.
The frictional force is 126.046 N
Explanation:
Given:
Mass of bullet kg
Thickness of sand bag m
Initial bullet velocity
Final bullet velocity
According to the work energy theorem,
Work done by friction force is equal to change in kinetic energy.
Here we have to find friction force
N
Here not any option is matching but only (A) option is near to our answer.
Therefore, the frictional force is 126.046 N
Answer:
im pretty sure its b
Note that when the acceleration is negative — on the interval [0, 2) — that means that the velocity is decreasing. When the acceleration is positive — on the interval (2, 4] — the velocity is increasing. Speeding up and slowing down.
Would that be 10?
.1 second per revolution, so 10 rps