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spayn [35]
3 years ago
11

5 mL of ethanol has a mass of 3.9 grams and 5.0 mL of benzene has a mass of 4.4 grams,

Chemistry
1 answer:
Sonja [21]3 years ago
8 0

Answer:

Benzene is more denser.

Explanation:

Given data:

Mass of ethanol = 3.9 g

Volume of ethanol = 5 mL

Volume of benzene = 5.0 mL

Mass of benzene = 4.4 g

which is denser = ?

Solution:

Density:

Density is equal to the mass of substance divided by its volume.

Units:

SI unit of density is Kg/m3.

Other units are given below,

g/cm3, g/mL , kg/L

Formula:

D=m/v

D= density

m=mass

V=volume

Symbol:

The symbol used for density is called rho. It is represented by ρ. However letter D can also be used to represent the density.

Density of ethanol:

d = m/v

d = 3.9 g/ 5 mL

d = 0.78 g/mL

Density of benzene:

d = m/v

d = 4.4 g/5.0 mL

d = 0.88 g/mL

So benzene is more denser.

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Answer:

The answer to your question is      SO₂   +   3H₂    ⇒     H₂S   + 2H₂O

Explanation:

Reaction

                                SO₂   +   H₂    ⇒     H₂S   +  H₂O

                      Reactants           Elements            Products

                              1                   Sulfur                    1

                               2                  Hydrogen               4

                              2                   Oxygen                   1

This reaction is unbalanced so we need to balance it.

                              SO₂   +   3H₂    ⇒     H₂S   + 2H₂O

                      Reactants           Elements            Products

                              1                   Sulfur                   1

                              6                  Hydrogen               6

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Now, the reaction is balanced

3 0
3 years ago
Determine the empirical and molecular formula:
Bingel [31]

Answer:

The empirical formula = molecular formula = C13H18O2

Explanation:

in 100% compound we have 75.6 % Carbon ( Molar mass = 12g/mole), 8.80% hydrogen ( Molar mass = 1.01 g/mole) and 15.5% Oxygen (Molar mass = 16.01 g/mole).

Carbon: 75.6g / 12 = 6.29

Hydrogen: 8.80/ 1 = 8.80

Oxygen: 15.5/ 16 = 0.97

⇒0.97 is the smallest so we divide everything through by 0.97

C: 6.29 / 0.97 =  6.48 ≈ 6.5

H: 8.80 /0.97 = 9

O: 0.97 / 0.97 = 1

To get rid of decimals, we multiply by 2  

C: 6.5 x 2 = 13

H: 9 x 2 = 18

O: 1 x 2 = 2

The empirical formula = C13H18O2

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The empirical formula = molecular formula = C13H18O2

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Secondary Amines:
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Tertiary Amines:
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