Answer:
The angular velocity I would have to rotate it in order to generate an emf of amplitude 1.0 V is 254.65 rad/s
Explanation:
given information:
B = 0.5 mT = 0.0005 T
N = 1000
r = 5 cm = 0.05 m
emf, ε = 1 V
according to Faraday's law
ε = -N dΦ/dt, Φ = B A
= - N d( B A)/dt
= - N d( B A cos ωt)/dt
= - N B A d(cos ωt)/dt
= N B A ω sin ωt
A = πr², so
ε = N B πr² ω sin ωt
where
ε = emf
N = number of coil turn
B = magnetic field
r = radius
ω = angular velocity
Φ = magnetic flux
emf maximum, sin ωt = 1. So,
ε = N B πr² ω
ω = ε/N B πr²
= 1/[(1000) (0.0005) π (0.05)²
= 254.65 rad/s
A.draw in the forces .Use the scale 1cm =10n of force
<span>The answer is that, Mass, time, and length are
the quantities that would change considering the speed of light as the limit. In
Einstein's equations it depends on velocity as a fraction of the speed of light.
we can take example as,
Appeared length = rest length x </span><span>(1-u</span>²<span>)</span>⁽¹/²⁾
<span>in this u is the velocity as a fraction
of the speed of light. </span>
The potential energy of the object is 78.4 J
Explanation:
The gravitational potential energy (GPE) of an object is the energy possessed by the object due to its position in a gravitational field.
For an object near the Earth's surface, the GPE is given by:
where
m is the mass of the object
is the acceleration of gravity near the Earth's surface
h is the height of the object relative to the surface
For the object in this problem,
m = 2 kg
h = 4 m
Substituting, we find its GPE:
Learn more about potential energy:
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Answer:
astatine
Explanation:
Sorry if this is wrong i am not a hundred percent sure.
