Question

The force in Newtons on a particle directed along the x-axis is given by F(x)=exp(−(x/5)+5) for x≥0 where x is in meters. The particle is constrained to move along the x-axis. Find the work done in Joules on the particle, W, in moving it from x=0 to x=1 using the fact that F=dW/dx. For your reference, 1 Joule = 1 Newton × 1 meter.

Answer 1

From F= dW/dx u will integrate nad will have : W = Integralfrom [0 to 1] (F(x) dx)  => W= Intgral [0..1] exp[ (-x/5)+5] dx all u need is to solve this integral.