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yKpoI14uk [10]
3 years ago
10

What cloud makes hail

Physics
1 answer:
MArishka [77]3 years ago
3 0

Answer:

Cumulonimbus

Hail development. Hail is a type of strong precipitation, which is shaped in rainstorms mists (Cumulonimbus). Tempests mists comprises of beads of fluid water (at temperatures lower than 0°с, the beads can be in a thermodynamically instable supercooled condition) and ice gems

Explanation:

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Answer:

Constructed cladograms all typically share certain key features: Root – The initial ancestor common to all organisms within the cladogram (incoming line shows it originates from a larger clade) Nodes – Each node corresponds to a hypothetical common ancestor that speciated to give rise to two (or more) daughter taxa.

Explanation:

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3 years ago
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What is the speed of a beam of electrons when under the simultaneous influence of E = 1.64×104 V/m B = 4.60×10−3 T Both fields a
andrezito [222]

Answer: v = 3.57×10^6 m/s; R = 4.42×10^-3m; T = 7.78×10^-9 s

Explanation:

Magnetic force(B) = 4.60×10^-3 T

Electric force(E) = 1.64×10^4 V/m

Both forces having equal magnitude ;

Magnetic force = electric force

qvB = qE

vB = E

v = (1.64×10^4) ÷ (4.60×10^-3)

v = 3.57×10^6 m/s

2.) Assume no electric field

qvB = ma

Where a = v^2 ÷ r

R = radius

a = acceleration

v = velocity

qvB = m(v^2 ÷ R)

R = (m×v) ÷ (|q|×B)

q=1.6×10^-19C

m = 9.11×10^-31kg

R = (9.11×10^-31 * 3.57×10^6) ÷ (1.6×10^-19 * 4.6×10^-3)

R = 32.5227×10^-25 ÷ 7.36×10^-22

R = 4.42×10^-3m

3.) period(T)

T = (2*pi*R) ÷ v

T = (2* 4.42×10^-3 * 3.142) ÷ (3.57×10^6)

T = (27.775×10^-3) ÷(3.57×10^6)

T = 7.78×10^-9 s

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4 years ago
Using a scale of 1 cm to represent 10 N , find the size and direction of the resultant of forces of 30 N and 40 N acting at righ
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Answer:

Hence, option (A) is correct answer.

Explanation:

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4 years ago
A lead bullet with 30-g of mass traveling at 600 m/s hits a thin iron wall and emerges at a speed of 300 m/s. Suppose 50% of the
TiliK225 [7]

Answer:

liquid state of lead T = 547ºC

Explanation:

The temperature change of the lead bullet can be found by the calorimetry equation  

      Q = m c_{v} ΔT  

Where heat is the energy transferred to lead during the crash, we can find average work  

      W = F x  

With the crash it is very short we can use the average speed of the projectile during the crash  

       v_{m} = (v_{f} + v₀) / 2 = (600 + 300) / 2  

       v_{m} = 450 m / s  

This speed of the projectile inside the wall is very inaccurate, but it is better than using any of the two speeds given (initial and final)  

       W = Δp vm  

       W = (m v_{f} -m v₀) vm  

       W = m ( v_{f} -v₀) vm  

       W = 30 10⁻³ (300-600) 450  

       W = 4050 J  

As we have a shock let's use the momentum  

       I = F t = ΔP  

       F = Δp / t  

Let's replace  

      W = (Dp / t) x  

With the crash it is very short we can use the average speed of the projectile during the crash  

     v_{m} = (v_{f} + v₀) / 2 = (600 + 300) / 2  

     v_{m} = 450 m / s  

This speed of the projectile inside the wall is very inaccurate, but it is better than using any of the two speeds given (initial and final)  

      W = Δp vm  

      W = (m v_{f} -m v₀) vm  

     W = m ( v_{f} -v₀) vm  

     W = 30 10⁻³ (300-600) 450  

     W = 4050 J  

They tell us that 50% of the heat is absorbed by lead  

     Q = 50% W  

     Q = 2025 J  

Let's calculate the temperature , the specific heat of lead is

      cv =  128 J/kg ºC  

     Q = m c_{v} Δt

     ΔT = Q / m c_{v}  

     ΔT = 2025 / 3010⁻³ 128  

     T_{f}= 547C

If we review the periodic table, the melting point of lead is 327.3ºC and the boiling point is 1726ºC, since it has a higher temperature than the lead must be in a liquid state

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This timeline correctly shows the order of time periods in the Mesozoic Era.
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It goes triassic, Jurassic, Cretaceous
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