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notsponge [240]

3 years ago

5

What is the 3rd term of a geometric sequence with a common ratio of 1/3 and a first term of 90

1 answer:

dangina [55]3 years ago

6 0

See below hope it helps

Answer: 90,30,10

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frez [133]

Answer:

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Step-by-step explanation:

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2 years ago

Which counterexample can be used to show that the following conjecture is false?

vitfil [10]

1and2 are supplementary angles is conjecture is false

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2 years ago

The house numbers on the North side of Flynn Street are even. In one block, the house numbers begin 1022, 1032, 1042, 1052. What

Gnom [1K]

The series 1022,1032,1042,1052....

a1=a=1022
d=a2-a1=1032-1022=10
n=5 as 5th term

Sn= a+(n-1)d
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3 0

3 years ago

Find the given term 11, -33,99 9th term

kvv77 [185]

Assuming the sequence goes on like this 11,-33,99,-297,891,...,
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So, the 9th term is
$a_9=-11\cdot(-1)^9\cdot3^{9-1}=-11\cdot(-1)\cdot6561=72171$

5 0

2 years ago

How do you write 2/20 as a percentage

Brut [27]

Answer:2/20 =

2 ÷ 20 =

0.1 =

0.1 × 100/100 =

0.1 × 100% =

Step-by-step explanation:

google

7 0

3 years ago