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notsponge [240]
3 years ago
5

What is the 3rd term of a geometric sequence with a common ratio of 1/3 and a first term of 90

Mathematics
1 answer:
dangina [55]3 years ago
6 0
See below hope it helps

Answer: 90,30,10

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what is the volume of a cylinder with height of 9 inches and the the radius is 1 inch. round to the nearest cubic inch
poizon [28]

Answer:

Step-by-step explanation:

Volume of cylinder can be calculated by using the formula V= pir^2h

Where r is radius of cylinder and h is the height.

A cylinder with radius 1 inch and height of 9 inch is given.

r=1,h=1,π=3.14.

Substituting the given values :

V=πr2h=π·12·9≈28.27433

Volume of cylinder rounded to nearest tenth is 28.27 cubic inches .

6 0
4 years ago
A bottle of soft drink is two thirds full. Jack drinks one quarter of the remaining soft drink. How full is the bottle now
marusya05 [52]

We know that the bottle of soft drink has a remaining volume which is 2 / 3 of the original.

Since Jack drank 1 / 4 of the remaining volume, hence only 3 / 4 now finally remains, the total is:

 

(2 / 3) * (3 / 4) = 6 / 12 = 1 / 2

 

<span>Hence the bottle is now one half full</span>

8 0
4 years ago
Read 2 more answers
IM RUNNING OUT IF TIME CAN SOMEONE PLEASE HELP
Elenna [48]

Answer:

the third option

Step-by-step explanation:

hope this helps! have a good day and stay safe!

3 0
3 years ago
The following data gives the speeds (in mph), as measured by radar, of 10 cars traveling north on I-15. 76 72 80 68 76 74 71 78
____ [38]

Answer:

71.123 mph ≤ μ ≤ 77.277 mph

Step-by-step explanation:

Taking into account that the speed of all cars traveling on this highway have a normal distribution and we can only know the mean and the standard deviation of the sample, the confidence interval for the mean is calculated as:

m-t_{a/2,n-1}\frac{s}{\sqrt{n} } ≤ μ ≤ m+t_{a/2,n-1}\frac{s}{\sqrt{n} }

Where m is the mean of the sample, s is the standard deviation of the sample, n is the size of the sample, μ is the mean speed of all cars, and t_{a/2,n-1} is the number for t-student distribution where a/2 is the amount of area in one tail and n-1 are the degrees of freedom.

the mean and the standard deviation of the sample are equal to 74.2 and 5.3083 respectively, the size of the sample is 10, the distribution t- student has 9 degrees of freedom and the value of a is 10%.

So, if we replace m by 74.2, s by 5.3083, n by 10 and t_{0.05,9} by 1.8331, we get that the 90% confidence interval for the mean speed is:

74.2-(1.8331)\frac{5.3083}{\sqrt{10} } ≤ μ ≤ 74.2+(1.8331)\frac{5.3083}{\sqrt{10} }

74.2 - 3.077 ≤ μ ≤ 74.2 + 3.077

71.123 ≤ μ ≤ 77.277

8 0
3 years ago
How can you compare ratios to solve a problem?
Sindrei [870]
“To use proportions to solve ratio word problems, we need to follow these steps:
Identify the known ratio and the unknown ratio.
Set up the proportion.
Cross-multiply and solve.
Check the answer by plugging the result into the unknown ratio.”
I hope this helps.
6 0
3 years ago
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