We can solve this problem by referring to the standard
probability distribution tables for z.
We are required to find for the number of samples given the
proportion (P = 5% = 0.05) and confidence level of 95%. This would give a value
of z equivalent to:
z = 1.96
Since the problem states that it should be within the true
proportion then p = 0.5
Now we can find for the sample size using the formula:
n = (z^2) p q /E^2
where,
<span> p = 0.5</span>
q = 1 – p = 0.5
E = estimate of 5% = 0.05
Substituting:
n = (1.96^2) 0.5 * 0.5 / 0.05^2
n = 384.16
<span>Around 385students are required.</span>
Answer:
which 1st page or 2nd page
The resulting equation after simplyfing the given equation is 3x^2 + 20x + 12 = 0 and whoose solutions are x = -2/3 or x = -6.
According to the given question.
We have an equation

So, to find the resulting equation of the above equation we need to simplify.
First we will take LCD



Multiply both the sides by x.

Again multiply both the sides by x



Factorize the above equation
⇒3x(x+6)+2(x+6) = 0
⇒(3x + 2)(x+6) = 0
⇒ x = -2/3 or x = -6
Hence, the resulting equation after simplyfing the given equation is 3x^2 + 20x + 12 = 0 and whoose solutions are x = -2/3 or x = -6.
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The answer is C.0,3 because One of Y equal 0 for X