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ddd [48]
3 years ago
15

A company produces a cardboard box in the shape of a rectangular prism. The surface area of the box is represented by S=10x2, wh

ere x is the length of the base. Find the inverse by solving for x without switching the variables.
Mathematics
1 answer:
OLEGan [10]3 years ago
5 0

S = 10x^2

S/10 = x^2

+or-sqrt(S/10) = x

+or- sqrt(S10)/10 = x

so

_inverse = +or-sqrt(10x)/10

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Find the equation of the line with Slope = 8 and passing through (3,28). Write your equation in the form
kvasek [131]

Answer:

y = 8x + 4

Step-by-step explanation:

y=mx+b

m=8

y = 8x + b

We just need to find b. B is where the line intersects the y- axis. On the y-axis by definition, the x-coordinate =0 but that is not helpful now...

Let's re write and try to solve for b. That means write as b = ...

y = 8x + b

b = y - (8x)

Substitute for x and y the numbers of the coordinates of the given point (3,28):

b = y - (8*x)

b = 28 - (8*3)

b = 28 - 24

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So the answer is y = 8x + 4

8 0
3 years ago
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White raven [17]
The answer is eight over fifteen ( 8/15)
4 0
3 years ago
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Assoli18 [71]

Answer:

94 cubic units

Step-by-step explanation:

The volume of this parallelepiped (the product of area of its base and height) is equal to the absolute value of the scalar triple product |\vec{t}\cdot (\vec{u}\times \vec{v})|

Since

\vec{t}=3\vec{i}-4\vec{j}-6\vec{k}=(3,-4,-6)\\ \\\vec{u}=3\vec{i}-7\vec{j}-7\vec{k}=(3,-7,-7)\\ \\\vec{v}=5\vec{i}+\vec{j}+3\vec{k}=(5,1,3)

we have

|\vec{t}\cdot (\vec{u}\times \vec{v})|=\left|\left|\begin{array}{ccc}3&-4&-6\\3&-7&-7\\5&1&3\end{array}\right|\right|=|3\cdot (-7)\cdot 3+(-4)\cdot (-7)\cdot 5+3\cdot 1\cdot (-6)-5\cdot (-7)\cdot (-6)-3\cdot (-7)\cdot 1-3\cdot (-4)\cdot 3|=|-63+140-18-210+21+36|=|-94|=94\ un^3.

4 0
3 years ago
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The answer is 2 Miles


I did (6+4)÷5 to find the answer

7 0
3 years ago
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ra1l [238]

Answer:

area = 385 cm²

Step-by-step explanation:

area = 5cm * 77cm

area = 385 cm²

8 0
3 years ago
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