If R1 = 6, R2 = 2 and VAΓ = 16 Find Roλ, I, VAB, VAΓ
1 answer:
Answer:
<em>Rt = 8 ohm</em>
<em>I = 2 A</em>
<em>Vab = 12 V</em>
<em>VbΓ = 4 V</em>
<em>VaΓ = 16 V</em>
Explanation:
<u>Electric Circuits</u>
We'll apply Ohm's formula to solve the circuit shown on the image:
V = R.I
Where V is the voltage, R is the resistance, and I is the current.
The circuit has two resistances connected in series, thus the total resistance is:
Rt = R1 + R2 = 6 ohm + 2 ohm = 8 ohm
Now the current is:
I = 2 A
The voltages are calculated below:
Vab = R1 * I = 6 ohm * 2 A = 12 V
VbΓ = R2 * I = 2 ohm * 2 A = 4 V
VaΓ = Vab + VbΓ = 12 V + 4 V = 16 V
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Answer:
A) B = 5.4 10⁻⁵ T, B) the positive side of the bar is to the West
Explanation:
A) For this exercise we must use the expression of Faraday's law for a moving body
fem =
fem = - d (B l y) / dt = - B lv
B =
we calculate
B = - 7.9 10⁻⁴ /(0.73 20)
B = 5.4 10⁻⁵ T
B) to determine which side of the bar is positive, we must use the right hand rule
the thumb points in the direction of the rod movement to the south, the magnetic field points in the horizontal direction and the rod is in the east-west direction.
Therefore the force points in the direction perpendicular to the velocity and the magnetic field is in the east direction; therefore the positive side of the bar is to the West